What does the line 4x -3y = 7 look like?

What would the altimeter read if Janelle were at sea level? What do the positive readings on the altimeter represent? What do th

marshall27 [118]

Answer:

umm i dont know but how did no one answer question

Step-by-step explanation:

7 0

3 years ago

Solve number problem 8

butalik [34]

Two consecutive odd integers have a difference of 2. If you let the smaller one of them be x, the other one is x + 2.

Their sum is -36, so add x and x + 2, and set equal to -36. Then solve for x to find the smaller one. Finally, 2 more than x is the greater of the two integers.

x + x + 2 = -36

2x + 2 = -36

2x = -38

x = -19

The smaller one of the two integers is -19.

x + 2 = -19 + 2 = -17

The greater of the two integers is -17.

Answer: The integers are -19 and -17.

4 0

3 years ago

Read 2 more answers

The results of Accounting Principals’ latest Workonomix survey indicate the average American worker spends $1092 on coffee annua

Nataly_w [17]

Answer:

a)

Group 18-34 years old

$\bar x = 1041.625 \\ s^2=485301 \\ s=696.635$

Group 35-44 years old

$\bar x = 1359.5 \\ s^2=178548 \\ s=422.549$

Group 45 and older

$\bar x = 1414.375 \\ s^2=18292.27 \\ s=135.248$

b)

According to the sample there is 9.04% probability that a person between 18 and 34 consume less than the average, 47.74% probability that a person between 35 and 44 consume more than the average and 50% probability that a person older than 45 consume more than the average.

Step-by-step explanation:

a)

The mean for each sample is

$\bar x=\frac{\sum_{k=1}^{10}x_k}{10}$

where the $x_k$ are the data corresponding to each group

The variance is

$s^2=\frac{\sum_{k=1}^{10}(\bar x-x_k)^2}{9}$

and the standard deviation is s, the square root of the variance.

Group 18-34 years old

$\bar x = 1041.625 \\ s^2=485301 \\ s=696.635$

Group 35-44 years old

$\bar x = 1359.5 \\ s^2=178548 \\ s=422.549$

Group 45 and older

$\bar x = 1414.375 \\ s^2=18292.27 \\ s=135.248$

b)

Let's compare these averages against the general media established of $1,092 by using the corresponding z-scores

$z=\frac{\bar x-\mu}{s/\sqrt{n}}$

where

$\bar x$ = mean of the sample

$\mu$ = established average

s = standard deviation of the sample

n = size of the sample

z-score of Group 18-34 years old

$z=\frac{1041.625-1092}{696.635/\sqrt{10}}=-0.2286$

The area under the normal curve N(0;1) between -0.2286 and 0 is 0.0904. So according to the sample there is 9.04% probability that a person between 18 and 34 consume less than the average.

z-score of Group 35-44 years old

$z=\frac{1359-1092}{422.5491/\sqrt{10}}=2.0019$

The area under the normal curve N(0;1) between 0 and 2.0019 is 0.4774. So according to the sample there is 47.74% probability that a person between 35 and 44 consume more than the average.

z-score of Group 45 and older

$z=\frac{1414.375-1092}{135.2489/\sqrt{10}}=7.5375$

The area under the normal curve N(0;1) between 0 and 7.5375 is 0.5. So according to the sample there is 50% probability that a person older than 45 consume more than the average.

3 0

4 years ago

Make x the subject of each of the following formulae: a) y = 2x - 1 b) y = x/2 + 3

julsineya [31]

Answer:

$1)y = 2x - 1 \\ y + 1 = 2x \\ \frac{y + 1}{2} = x \\ 2)y = \frac{x}{2} + 3 \\ y - 3 = \frac{x}{2} \\ 2(y - 3) = x \\ 2y - 6 = x \\ thank \: you$