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3 years ago

What does the line 4x -3y = 7 look like?

Mathematics

2 answers:

belka [17]3 years ago

4 0

Upright and maybe tilted

AlexFokin [52]3 years ago

3 0

C) tilted right upward

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given f(x) = 3/2x - 5 and g(x) = x^2 + 2x find x (the input) if g(x) = 0 ( the output 0 ) there are 2 answers

MariettaO [177]

if g(x) = 0, then

x = 0 -- > g(0) = 0^2 + 2(0) = 0 + 0

AND x = -2 --> g(-2) = -2^2 + 2(-2) = 4 + (-4) = 0.

I don't know why f(x) was given at all, but when x = 0, f(0) = -5, and when x = -2, f(-2) = -8.

5 0

3 years ago

Number 16. I need help with this!!!!

Amanda [17]

If number 16 is the one i think it is then the answer is no. She is not 6 miles above the ground. She is 5.5 miles above the ground. There is 5280 ft in one mile. divide 29040 by 5280

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4 years ago

Please help me I’ve been struggling

Shalnov [3]

Your answer will be 5.
Hope this helps!

3 0

3 years ago

IF Tunde, who has n eggs, has three more than Sola, how many eggs has Sola?

gtnhenbr [62]

Answer:

Sola has n-3 eggs

Step-by-step explanation:

Tunde = n

Tunde has 3 more = Sola has 3 less than tunde

= Tunde - 3

= n - 3

8 0

3 years ago

Determine whether the Mean Value Theorem can be applied to f on the closed interval [a, b]. If the Mean Value Theorem can be app

Gnesinka [82]

Answer:

There is a value of $c$ in (-1, 1), $c = 0.577$ .

Step-by-step explanation:

Let $f(x) = x^{3}+2\cdot x$ for $x \in[-1,1]$ , we need to prove that $f(x)$ is continuous and differentiable to apply the Mean Value Theorem. Given that $f(x)$ is a polynomical function, its domain comprises all real numbers and therefore, function is continuous.

If $f(x)$ is differentiable, then $f'(x)$ exists for all value of $x$ . By definition of derivative, we obtain the following expression:

$f'(x) = \lim_{h \to 0} \frac{f(x+h)-f(x)}{h}$

$f'(x) = \lim_{h \to 0} \frac{(x+h)^{3}+2\cdot (x+h)-x^{3}-2\cdot x}{h}$

$f'(x) = \lim_{h \to 0} \frac{x^{3}+3\cdot x^{2}\cdot h+3\cdot x\cdot h^{2}+h^{3}+2\cdot x+2\cdot h-x^{3}-2\cdot x}{h}$

$f'(x) = \lim_{h \to 0} \frac{3\cdot x^{2}\cdot h+3\cdot x\cdot h^{2}+h^{3}+2\cdot h}{h}$

$f'(x) = \lim_{h \to 0} 3\cdot x^{2}+ \lim_{h \to 0} 3\cdot x \cdot h+ \lim_{h \to 0} h^{2}+ \lim_{h \to 0} 2$

$f'(x) = 3\cdot x^{2}+2$ (Eq. 2)

The derivative of a cubic function is quadratic function, which is also a polynomic function. Hence, the function is differentiable at the given interval.

According to the Mean Value Theorem, the following relationship is fulfilled:

$f'(c) = \frac{f(1)-f(-1)}{1-(-1)}$ (Eq. 3)