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3 years ago

Please help me I’ve been struggling

Mathematics

1 answer:

Shalnov [3]3 years ago

3 0

Your answer will be 5.
Hope this helps!

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Evaluate the given algebraic expression for x = 7 and y = 3. 2(x + y)2 A.)20 B.)42 C.)200 D.)400

horrorfan [7]

A. you would put in 7 for X and 3 for Y.
3 + 7 = 10
2(10) = 20

6 0

3 years ago

Read 2 more answers

A scuba diver is 240 feet below sea level and descends 50 feet further down to observe the sea life.

taurus [48]

Answer:

The new position is 190 feet below sea

Step-by-step explanation:

240-50=190

8 0

3 years ago

Read 2 more answers

Help can someone please help me

kkurt [141]

Answer:

B=55

Step-by-step explanation:

2x+3x+2x+5=180

7x=175

X=25

B= 2x+5

B=2*25 +5

B=55

7 0

3 years ago

A scientist used a microscope to count the number of bacterial cells in a petri dish every hour. The graph shows the data collec

Alex777 [14]

The required relationship shown by the graph is the exponential relationship $n =2^t$ . Option a is correct,

Given that,

A graph has been shown, showing the data, what is the relationship between the number of bacteria with time is to be determined.

<h3>What is a graph?</h3>

The graph is a demonstration of curves that gives the relationship between the x and y-axis.

Since the recorded value from the graph is
At, t = 1 ; n = 2
At t = 2 ; n = 4
At t = 3 ; n = 8
At t = 4 ; n = 16
At t = 5 : n = 32
Here the above data show the exponential relation between n and t with the base value 2 i.e. $n =2^t$

Thus, the required relationship shown by the graph is the exponential relationship of $n =2^t$ . Option a is correct,

Learn more about graphs here:

brainly.com/question/16608196

#SPJ1

8 0

1 year ago

The radius of a sphere is increasing at a rate of 2 mm/s. How fast is the volume increasing (in mm3/s) when the diameter is 40 m

daser333 [38]

Answer:

$\dfrac{dV}{dt}=502.65\ mm^3/s$

Step-by-step explanation:

The volume of a sphere is given by :

$V=\dfrac{4}{3}\pi r^3$

The rate of change of volume means,

$\dfrac{dV}{dt}=\dfrac{d}{dt}(\dfrac{4}{3}\pi r^3)\\\\\dfrac{dV}{dt}=\dfrac{4}{3}\pi \times 3r\times \dfrac{dr}{dt}$

We have, $\dfrac{dr}{dt}=2\ mm/s\ and\ r=40\ mm$

So,

$\dfrac{dV}{dt}=\dfrac{4}{3}\pi \times 3\times 20\times 2\\\\=502.65\ mm^3/s$

So, the volume is increasing at the rate of $502.65\ mm^3/s$ .

6 0

3 years ago