Answer:
The surface area is equal to 
Step-by-step explanation:
The surface area of the triangular pyramid is equal to the area of its four triangular faces
so
In this problem
![SA=4[\frac{1}{2}(b)(h)]](https://tex.z-dn.net/?f=SA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29%5D)
we have


substitute the values
![SA=4[\frac{1}{2}(15)(13)]=390\ in^{2}](https://tex.z-dn.net/?f=SA%3D4%5B%5Cfrac%7B1%7D%7B2%7D%2815%29%2813%29%5D%3D390%5C%20in%5E%7B2%7D)
Answer:
35) x = 3 1/3
Step-by-step explanation:
for each of these parallelograms, the diagonals are congruent
in #35, DT = RT so you can set their expressions equal to each other
22 = 6x + 2
20 = 6x
20/6 = x
10/3 = x (simplified)
First,multiply the -2 by everything in the brackets
so that's, -6x-(b-4x)+(x+6b)
then combine like terms
that's -6x-(7b-3x) which is
-3x-7b I believe