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ivann1987 [24]
3 years ago
6

Describe three events about matter and energy that cannot be explained

Physics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer:

As anything that has mass and takes up space. Matter is found in 3 major states; solid, liquid and gas. Atoms are the smallest particle of matter. They are so small that you cannot see them with your eyes or even with a standard microscope.

Have a good day! :D

Explanation:

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A gas cylinder is filled with 4.00 moles of oxygen gas at 300.0 k. the piston is compressed to yield a pressure of 400.0 kpa. wh
Radda [10]
To answer this item, it is assumed that the gas in the cylinder is ideal such that it follows the equation,
                                        PV = nRT
when V is to be calculated,
                                              V = nRT/P
        V = (4)(0.0821 L.atm/molK)(300 K) / (400 kPa/101.325 kPa/atm)  
                                                V = 24.95 L
Thus, the volume of gas in the cylinder is 24.95 L. 
8 0
3 years ago
Why does the area around the equator stay about the same temperature year round?
Verdich [7]
Axial Tilt and Sun Energy

This axial tilt means that during the Earth's journey around the sun the poles receive varying amounts of sunlight. The equator, however, receives relatively consistent sunlight all year. The consistency of energy means the equator's temperature stays relatively constant all year.
3 0
3 years ago
A space probe recovered an 8.5-kg sample of rocks from the surface of Mars. The acceleration due to gravity on Mars is 3.7 meter
Nataliya [291]

Answer: 31N

Explanation:F = m x a

F = 8.5 x 3.7

F = 31.45

F = 31 (rounded)

F = 31 N

3 0
3 years ago
Three capacitors with individual capacitances of 2 μF, 5 μF, and 10 μF
rodikova [14]

Answer:

1.25C

Explanation:

When capacitance is in series we add them like this: 1/Ctotal = 1/C1 +1/C2 + 1/C3.....

1/C = 1/2 + 1/5 + 1/10 = 5 + 2 + 1/10 = 8/10

C = 10/8 = 1.25

Capacitance = Charge/potential difference(Q/V)

1.25 = Charge/12

Total charge = 1.25 ×12 =15coulombs

5 0
3 years ago
Calculate the percentage increase in length of a wire of diameter 2.2 mm stretched by a load of
vesna_86 [32]

Answer:

0.21%

Explanation:

We are given;

Mass; m = 100 kg

Diameter; d = 2.2 mm = 2.2 × 10^(-3) m

Young's modulus; E = 12.5 x 10^(10) N/m².

Formula for area is;

A = πd²/4

A = (π/4) x (2.2 x 10^(-3))²

A = 3.8 x 10^(-6) m²

Force; F = mg

g is acceleration due to gravity and has a constant value of 9.8 m/s²

F = 100 × 9.8

F = 980 N

Formula for young's modulus is;

E = Stress/strain

Formula for stress = F/A

Formula for strain = ΔL/L

Thus;

E = (F/A)/(ΔL/L)

Making ΔL/L the subject, we have;

ΔL/L = (F/A)/E

Plugging in the relevant values;

ΔL/L = 980/(3.8 x 10^(-6) × 12.5 × 10^(10))

ΔL/L = 0.0021

Then percentage increase in length of a wire = 0.0021 × 100% = 0.21%

8 0
3 years ago
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