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xxMikexx [17]
4 years ago
7

Two small metal spheres are 25 cm apaft.The spheres have equal amount of negative charge and repel each other with a force of 0.

036 N. What is the magnitude of the charge on each sphere? (a) 2x10-3 C (h) 3 x 10-4C
Physics
1 answer:
Mars2501 [29]4 years ago
8 0

Answer:

0.5\times 10^{-6}C

Explanation:

According to coulombs law force between two charges is given by F=\frac{1}{4\pi \epsilon _0}\frac{Q_1Q_2}{R^2} here R is the distance between both the charges which is given as 25 cm

We have given force F =0.036 N

So  0.036=\frac{1}{4\pi \times 8.85\times 10^{-12}}\frac{Q^2}{(0.25^2)} As \epsilon _0 is constant which value is 8.85\times 10^{-12}

Q^2=0.250\times 10^{-12}

Q=0.5\times 10^{-6}C

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Alisiya [41]

Answer:

x ’= 368.61 m,  y ’= 258.11 m

Explanation:

To solve this problem we must find the projections of the point on the new vectors of the rotated system  θ = 35º

            x’= R cos 35

            y’= R sin 35

           

The modulus vector can be found using the Pythagorean theorem

            R² = x² + y²

            R = 450 m

we calculate

            x ’= 450 cos 35

            x ’= 368.61 m

            y ’= 450 sin 35

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3 years ago
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4 years ago
LARGER vibration produces a higher ............
balandron [24]
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8 0
4 years ago
in positive numbers less than 1, the zeros between the decimal point and a non-zero number are _______ significant?
DedPeter [7]

Answer:

Explanation:

If a number of less than 1, then the number has a decimal point like

0.085, 0.008 e.t.c.

The zeros before the none zero digit are insignificant. The significant figure is 8 and 5.

But if there a zero between the none zero e.g. 0.0087056

Here the zero between 7 and 5 is significant, then the significant numbers are 8,7,0,5,6

But if the zero is not in between the none zero digit, then the zero is insignificant

E.g 0.05800

The last two zero is insignificant, the significant number is 5 and 8

So, If a positive numbers less than 1, the zeros between the decimal point and a non-zero number are NOT significant.

8 0
3 years ago
What is the velocity of a worm moving 1 meter in 2 hours to the East?
malfutka [58]

Answer:

Velocity = 0.0001389 m/s

Explanation:

Given that the

Distance covered = 1 metre

Time taken = 2 hours

Convert the hour to second

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Velocity = distance/ time

Velocity = 1/7200

Velocity = 0.0001389 m/s

3 0
4 years ago
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