The energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.
<h3>Conservation of energy</h3>
The amount of energy lost due to air resistance while she was bouncing is determined from the principle of conservation of energy.
ΔE = P.E - Ux
ΔE = mgh - ¹/₂kx²
ΔE = (50)(9.8)(16) - ¹/₂(35)(16)²
ΔE = 3,360 J
Thus, the energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.
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Answer:
1. 0 vh g
Explanation:
As air resistance is negligible, horizontal speaking, nothing is affecting the velocity. So the horizontal velocity of the projectile stays the same, vh.
As for vertical velocity, since there's always a constant gravitational acceleration acting downward, namely g, the vertical speed will decrease until it reaches the top where it is 0, it then starting to increase in magnitude, downward, due to its gravitational acceleration g.
Answer:
t=L/
Explanation:
<u>solution:</u>
Let E be an observer, and B a second observer traveling with velocity 
as measured by E. If E measures the velocity of an object A as 
then B will measure A velocity as
= -
Applied here,
the walkway (W) and the man (M) are moving relative to Earth (E}, the velocity of the man relative to the moving walkway is
= 
- 
,
The time required for the woman, traveling at constant speed relative to the ground, to travel distance L relative to the ground is
:
t=L/
Answer: it becomes a positive ion
Explanation:
So, when an atom loses 2 electrons there will be no change in the number of neutrons. Therefore, an isotope will not form. Thus, it is concluded that when an atom with no charge loses two electrons, it becomes a positive ion.
