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Marat540 [252]
3 years ago
9

lines of latitude a. run from north to south b.start greenwitch,greenland c. are parallel to the equator d.indicate magnetic dec

lination.
Physics
2 answers:
Archy [21]3 years ago
8 0
Lines of latitude are parallel to the equator. This is a big part of the reason that they are often called parallels of latitude.
kenny6666 [7]3 years ago
4 0
The answer is C.
they run east to west which makes them parallel to the equator and they measure distances north and south. 
I hope this helps.
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If you walk 800m north, 600m east, and 200 meters south at a speed of 1m/s. What is your velocity?
ryzh [129]

Answer:

0.375 m/s north & 0.375 m/s east

Explanation:

8 0
3 years ago
A box of volume V has a movable partition separating it into two compartments. The left compartment contains 3000 particles, the
storchak [24]

Answer:

a) V1 = 4V - V2/3 and V2 = 4V -  3V1

b) Δe = 4000V - 4000V2 + 9000V1

Explanation:

Let V represent volume of the box containing the two compartments

V1 represents compartment of the left compartment

V2 represents compartment of the right compartment

Momentum of the compartments before impact:

3000V1 + 1000V2

Momentum of the compartments after impact:

V(3000 + 1000) = 4000V

a) To obtain the volume of each compartment, that is, V1 and V2, we say:

Momentum before impact = Momentum after impact

3000V1 + 1000V2 = 4000V

∴ V1 = 4000V - 1000V2/3000 = 4V - V2/3

Also, V2 = 4000V - 3000V1/1000 = 4V - 3V1

b) Change in entropy,Δe = 4000V1 - 1000V2

By substituting the V1 and V2, we have:

4000(4V - V2)/3 - 1000(4V - 3V1)

16000V - 4000V2/3 - 4000V + 3000V1

16000V -  4000V2 - 12000V + 9000V1

∴ Δe = 4000V - 4000V2 + 9000V1

6 0
3 years ago
A microfarad capacitor is charged via a 12v battery. there is 1 kohms resistor in series with the capacitor. how much current is
olga2289 [7]
The answer completely depends on the number that belongs in the space before the word "microfarad".
7 0
3 years ago
2. Conner flips a coin up in the air (to determine if he or his sister needs to do the dishes) at an upward velocity of 4.00 m/s
Lana71 [14]

Answer:

5.6

Explanation:

Not so sure

4 0
2 years ago
39 g aluminum spoon (specific heat 0.904 J/g·°C) at 24°C is placed in 166 mL (166 g) of coffee at 83°C and the temperature of th
tatuchka [14]

<u>Answer:</u> The final temperature of the solution is 80.14^oC

<u>Explanation:</u>

The amount of heat released by coffee will be absorbed by aluminium spoon.

Thus, \text{heat}_{absorbed}=\text{heat}_{released}

To calculate the amount of heat released or absorbed, we use the equation:  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

Also,

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]    ..........(1)

where,

q = heat absorbed or released

m_1 = mass of aluminium = 39 g

m_2 = mass of coffee = 166 g

T_{final} = final temperature = ?

T_1 = temperature of aluminium = 24^oC

T_2 = temperature of coffee = 83^oC

c_1 = specific heat of aluminium = 0.904J/g^oC

c_2 = specific heat of coffee= 4.1801J/g^oC

Putting all the values in equation 1, we get:

39\times 0.904\times (T_{final}-24)=-[166\times 4.1801\times (T_{final}-83)]

T_{final}=80.14^oC

Hence, the final temperature of the solution is 80.14^oC

4 0
4 years ago
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