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Luden [163]
2 years ago
12

Please help me!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
ollegr [7]2 years ago
7 0
Your answer would be either A...or D.
kolezko [41]2 years ago
5 0
I believe it is "D" I know it's not "C" or "B"
You might be interested in
the marks in an examination for a Physics paper have normal distribution with mean μ and variance σ2 . 10% of the students obtai
Blababa [14]

Let X be the random variable for the number of marks a given student receives on the exam.

10% of students obtain more than 75 marks, so

P(X>75)=P\left(\dfrac{X-\mu}\sigma>\dfrac{75-\mu}\sigma\right)=P(Z>z_1)=0.10

where Z follows a standard normal distribution. The critical value for an upper-tail probability of 10% is

P(Z>z_1)=1-F_Z(z_1)=0.10\implies z_1=F_Z^{-1}(0.90)

where F_Z(z)=P(Z\le z) denotes the CDF of Z, and F_Z^{-1} denotes the inverse CDF. We have

z_1=F_Z^{-1}(0.90)\approx1.2816

Similarly, because 20% of students obtain less than 40 marks, we have

P(X

so that

P(Z

Then \mu,\sigma are such that

\dfrac{75-\mu}\sigma\approx1.2816\implies75\approx\mu+1.2816\sigma

\dfrac{40-\mu}\sigma\approx-0.8416\implies40\approx\mu-0.8416\sigma

and we find

\mu\approx53.8739,\sigma\approx16.4848

3 0
3 years ago
What is another way to write the calculation add 16 and 25, and then multiply by 47?
GarryVolchara [31]

Answer:

(16+25)×47

Step-by-step explanation:

..........

8 0
2 years ago
Read 2 more answers
Just want to check to make sure this is right. I got 81 as the average so D seemed right.
sergiy2304 [10]
Im not 100% sure but im pretty sure you are right brother! God bless...Good luck!
6 0
3 years ago
Need help on this one too ​
KiRa [710]

I think it's none because that should be communitive and that's not there so.

4 0
2 years ago
16+64846 what is the answer
astra-53 [7]
64,862 is the answer.
5 0
3 years ago
Read 2 more answers
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