Ask question

Ask question

All categories

3 years ago

14

The sum of the speeds of two trains is 724.3 miles per hour. If the speed of the first train is 11.7 mph faster than that of the

second train, find the speeds of each.

1 answer:

oee [108]3 years ago

8 0

Answer:

A=368 miles

B= 356.3 miles

Step-by-step explanation:

Given data

Let the two trains be A and B

A+B=724.3----------1

A-B=11.7--------------2

From eqn 1

A= 724.3-B

put this in place of A in eqn 2

724.3-B-B= 11.7

724.3-2B= 11.7

724.3-11.7= 2B

712.6=2B

B= 712.6/2

B= 356.3 miles

Put B=356.3 in eqn 1

A+356.3=724.3----------1

A= 724.3-356.3

A=368 miles

You might be interested in

A manager wants to determine if an employee training program has increased her employees’ customer satisfaction ratings. She ran

lubasha [3.4K]

Answer:

A

Step-by-step explanation:

The answer should be A
I hope that's ok if I am wrong pls correct me

6 0

2 years ago

write the equation of the line that is parallel to the line y = 2x 2 and passes through the point (5, 3). a. y = 2x - 7 b. y=-1/

Jlenok [28]

Parallel lines has equal slopes. Line y = 2x + 2 has a slope of 2, hence required slope is 2
Required equation is y - y1 = 2(x - x1)
y - 3 = 2(x - 5)
y - 3 = 2x - 10
y = 2x - 10 + 3
y = 2x - 7

5 0

3 years ago

Solve the equation -5 = c/7

sweet-ann [11.9K]

Multiply both sides by 7.

-5 * 7 = c/7 * 7

-5 * 7 = c

c = -35

Your final answer is c = -35.

3 0

3 years ago

Read 2 more answers

Can someone please help me

MrMuchimi

Answer:

Men it's a really long process and I've just woken up men

6 0

3 years ago

Read 2 more answers

The equation y = \large 1\frac{1}{2}x represents the number of cups of dried fruit, y, needed to make x pounds of granola. Deter

Natasha2012 [34]

Answer:

$(1\frac{1}{2},1)$ - False

$(4,6)$ - True

$(18,12)$ -- False

$(0,0)$ -- True

$(2\frac{1}{2},3\frac{3}{4})$ -- True

Step-by-step explanation:

The points are

$(1\frac{1}{2},1)$ , $(4,6)$ , $(18,12)$ , $(0,0)$ and $(2\frac{1}{2},3\frac{3}{4})$ ---- missing from the question

Given

$y = 1\frac{1}{2}x$

Required

Determine if each of the points would be on $y = 1\frac{1}{2}x$

To do this, we simply substitute the value of x and of each point in $y = 1\frac{1}{2}x$ .

(a) $(1\frac{1}{2},1)$

In this case;

$x = 1\frac{1}{2}$ and $y = 1$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 1\frac{1}{2}$

$y = \frac{3}{2} * \frac{3}{2}$

$y = \frac{9}{4}$

$y = 2\frac{1}{4}$

<em>The point </em> $(1\frac{1}{2},1)$ <em> won't be on the graph because the corresponding value of y for </em> $x = 1\frac{1}{2}$ <em> is </em> $y = 2\frac{1}{4}$ <em></em>

(b) $(4,6)$

In this case;

$x = 4$

$y = 6$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 4$

$y = \frac{3}{2} * 4$

$y = \frac{3* 4}{2}$

$y = \frac{12}{2}$

$y = 6$

<em>The point </em> $(4,6)$ <em> would be on the graph because the corresponding value of y for </em> $x = 4$ is $y = 6$

(c) $(18,12)$

In this case:

$x = 18;y = 12$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 18$

$y = \frac{3}{2} * 18$

$y = \frac{3* 18}{2}$

$y = \frac{54}{2}$

$y = 27$

<em>The point </em> $(18,12)$ <em> wouldn't be on the graph because the corresponding value of y for </em> $x = 18$ <em> is </em> $y = 12$ <em></em>

(d) $(0,0)$

In this case;

$x =0; y = 0$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 0$

$y = 0$

<em>The point </em> $(0,0)$ <em> would be on the graph because the corresponding value of y for </em> $x = 0$ is $y = 0$

(e) $(2\frac{1}{2},3\frac{3}{4})$

In this case:

$x = 2\frac{1}{2}$ ; $y = 3\frac{3}{4}$

$y = 1\frac{1}{2}x$ becomes

$y = 1\frac{1}{2} * 2\frac{1}{2}$

$y = \frac{3}{2} * \frac{5}{2}$

$y = \frac{15}{4}$

$y = 3\frac{3}{4}$

<em>The point </em> $(2\frac{1}{2},3\frac{3}{4})$ <em> would be on the graph because the corresponding value of y for </em> $x = 2\frac{1}{2}$ is $y = 3\frac{3}{4}$

3 0

3 years ago