Answer:
$0.025x² . . . where x is a number of percentage points
Step-by-step explanation:
The multiplier for semi-annual compounding will be ...
(1 + x/2)² = 1 + x + x²/4
The multiplier for annual compounding will be ...
1 + x
The multiplier for semiannual compounding is greater by ...
(1 + x + x²/4) - (1 + x) = x²/4
Maria's interest will be greater by $1000×(x²/4) = $250x², where x is a decimal fraction.
If x is a percent value, as in x = 6 when x percent = 6%, then the difference amount is ...
$250·(x/100)² = $0.025x² . . . where x is a number of percentage points
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<u>Example</u>:
For x percent = 6%, the difference in interest earned on $1000 for one year is $0.025×6² = $0.90.
Disagree she needs 7 cups of bananas because 1.75×4=7
Step-by-step explanation:
There are no choices available, so here is a graph of that equation. Simply compare it to the answer.
Answer:
|96.55−0.02|= x
|96.55+0.02|=x
Step-by-step explanation:
Given that:
Measured length of beam = 96.55 cm
Measurement accuracy = plus or minus (± 0.02cm)
Limits of actual length of the beam:
Let limit of actual length = x
Lower limit :
|measured length - accuracy| = x
|96.55 - 0.02| = x
96.53) x
Upper limit :
|measured length + accuracy| = x
|96.55 + 0.02| = x
96.57 = x
Answer:
theres an app thhat can help trust me i understand its hard lolll
Step-by-step explanation:
