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8090 [49]
2 years ago
11

Tran flips a coin 4 times. Which is true? Select two answers.

Mathematics
2 answers:
expeople1 [14]2 years ago
4 0

Answer:

D and E.

Step-by-step explanation:

D. For each toss you either get a head or a tail , 2 outcomes,  so for 4 tosses the number of outcomes = 2*2*2*2 = 16.

E.  As it is a fair coin all outcomes are equally likely.

irina1246 [14]2 years ago
3 0

Answer:

D. There are 16 possible outcomes.

E. All outcomes are equally likely.

<em>Hope this helps</em>

<em>-Amelia The Unknown</em>

I may not be sure though..

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Combining like terms<br><br> simplify the expression<br> n - 10 + 9n - 3
ohaa [14]
N-10+9n-3
n+9n=10n
10-3=7
so the answer is....
-13+10n

5 0
3 years ago
Read 2 more answers
9x - 4/x = 3. How to solve this? What is the value of x?
Ket [755]
9x-4/x=3 ok first lets get the like terms together! So 9x+1x=10x rewrite 10x-4=3 add 4 to both sides 10x=7 then divide 10 7/10=.7 x=.7
Or you can do it this way
9x-4/x=3 combine like terms so times -4 to both sides 3*-4=-12 rewrite 9x+x=-12 combine like term (still got some) 9x+1x=10x rewrite 10x=-12 divide 10 to both sides -12/10=-1.2 rewrite x=-1.2 (I'm like 95% sure it's this one) hope this helps!!! Have a nice nite (Don't be afraid to ask me about details on this or another question)!!!
7 0
3 years ago
A pair of Air Force 1 shoes went from $40 to $48. What is the percent increase for these shoes?
kompoz [17]

Answer:

Hi, the price went up by 20%

Hope this helps

6 0
3 years ago
Car Mileage for a
Mila [183]

Answer:

60

Step-by-step explanation:

4 0
3 years ago
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Discuss the validity of the following statement. If the statement is always​ true, explain why. If​ not, give a counterexample.
Zarrin [17]

Correction:

Because F is not present in the statement, instead of working on​P(E)P(F) = P(E∩F), I worked on

P(E∩E') = P(E)P(E').

Answer:

The case is not always true.

Step-by-step explanation:

Given that the odds for E equals the odds against E', then it is correct to say that the E and E' do not intersect.

And for any two mutually exclusive events, E and E',

P(E∩E') = 0

Suppose P(E) is not equal to zero, and P(E') is not equal to zero, then

P(E)P(E') cannot be equal to zero.

So

P(E)P(E') ≠ 0

This makes P(E∩E') different from P(E)P(E')

Therefore,

P(E∩E') ≠ P(E)P(E') in this case.

8 0
3 years ago
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