Well as it looks like to me the cords of the a,b,c are 2,3,1
Answer:
4,320
Step-by-step explanation:
7 is closer to 10 then 0. 4,310 + 10 = 4,320
Answer:
f(5) = 26.672 which is option D
Step-by-step explanation:
From question, f(1) = 2 and f'(x)=√(x^3 + 6)
f(5) = f(1) + (5,1)∫ f'(x) dx
Integrating using the boundary 5 and 1;
f(5) = 2 + (5,1)∫√(x^3 + 6) dx
f(5) = 2 + 24.672
So f(5) = 26.672
PART A:
The given quadratic equation is 2x²-10x-8=0
The radicand is given by b²-4ac where a, b, and c are the constants in a quadratic form ax²+bx+c
From the given equation, we have
a = 2
b = -10
c = -8
Radicand b²-4ac = (-10)² - 4(2)(-8) = 100 + 64 = 164
The radicand is >0 hence the quadratic equation has two distinct roots
PART B:
4x²-12x+5 = 0
We can use the factorization method to solve the equation
Firstly, we multiply 4 by 5 to get 20
Then we find the pair of numbers that multiply gives 20 and sum gives -12
The pair of number is -2 and -10
Rewriting the equation
4x²-2x-10x+5 = 0
2x(2x-1)-5(2x-1) = 0
(2x-1)(2x-5) = 0
2x-1 = 0 and 2x-5 = 0
x = 1/2 and x = 5/2
