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ValentinkaMS [17]
3 years ago
11

Janie has 4 pieces of fruit. 2 of the pieces of fruit are bananas. Write 2 fractions that describe the fraction of fruit that ar

e banana
Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
8 0

Answer:

1/2

Step-by-step explanation:

4 fruit and 2 of them are banana so 2/4

banana go on top and total number of fruit go on bottom

to simplify divide numerator and denominator by 2

2/2          1

------ = ---------

4/2          2        

Virty [35]3 years ago
7 0

Answer:

fractions that represent bananas are   \frac{2}{4}  &  \frac{1}{2}

Step-by-step explanation:

Given: Total No. of Fruits = 4

           No. of Bananas in all fruits = 2

To find: 2 fractions that describe the no of bananas in fruits.

As, we know

Fraction\: for\: given\: quantity = \frac{No.\: of\: given\: quantity}{Total \:no\: of\: quantities}

⇒ Fraction for bananas = \frac{2}{4}

                                         = \frac{1}{2}  {Simplest term}

Therefore, 2 fractions that represent bananas are   \frac{2}{4}  &  \frac{1}{2}

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4 0
3 years ago
Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

Multiply equation A by 10 both sides to remove the fractions

5x-2y=10 ----> equation C

isolate the variable y in equation B

y=\frac{x}{3}+8 ----> equation D

we have the system of equations

5x-2y=10 ----> equation C

y=\frac{x}{3}+8 ----> equation D

Solve the system by substitution

substitute equation D in equation C

5x-2(\frac{x}{3}+8)=10

solve for x

5x-\frac{2x}{3}-16=10

Multiply by 3 both sides

15x-2x-48=30

15x-2x=48+30

Combine like terms

13x=78

x=6

<em>Find the value of y</em>

y=\frac{x}{3}+8

y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

(22-5y)y=21

solve for y

22y-5y^2=21

5y^2-22y+21=0

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

x=22-5(1.4)=15

For y=3

x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0
3 years ago
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6 0
3 years ago
Read 2 more answers
PLEASE HELP!!
aliya0001 [1]

Ik this is late, but people who are looking for the answer can see this.

Answer:

an =1/3*6^n-1

Step-by-step explanation:

You should plug in 2 for n in each equation, which, the correct one should give you 2. Then, to make sure, you plug in 3 in the equations that gave you 2.

Example:

an = 1/3 * 6 ^n-1

Plug in 2.

an = 1/3 * 6 ^2-1

an = 1/3 * 6 ^1

1/3 * 6 = 2

Step 2.

an = 1/3 * 6 ^3-1

an = 1/3 * 6 ^2

1/3 * 36 = 12

Hope this helps.

4 0
3 years ago
Need some help with the question in the image​
goldfiish [28.3K]

Step-by-step explanation:

cost of 1 kg of jam = x

cost of 1 kg of butter = y

3x + 2y = 29 .....1

6x + 3y = 54 .....2

.....1 × 2 both sides of equation

6x + 4y = 58 .....3

.....3 - ......2

y = 4

replace y = 4 in 1......

3x + 8 = 29

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2 years ago
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