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lukranit [14]
3 years ago
8

HELP! SOMEWHERE AROUND 20 POINTS

Mathematics
1 answer:
Aleks [24]3 years ago
4 0

❤️Hello!❤️ A. is 6.80 inches, B. is 6.28 inches, C. is 776.470, D. is 840.764, so the standard bike will get you their faster. Hope this helps!↪️ Autumn ↩️

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2:3 ratio 
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6 0
3 years ago
Please answer this in two minutes
tangare [24]

Answer:

<h2>H = 60° </h2>

Step-by-step explanation:

To find angle H we use tan

tan ∅ = opposite / adjacent

From the question

The opposite is 2√21

The adjacent is 2√7

So that's

tan H = 2√21/ 2√7

H= tan-¹ 2√21/ 2√7

<h3>H = 60° </h3>

Hope this helps you

8 0
3 years ago
NEED THESE ANSWERED ASAP SO I CAN GRADUATE THIS WEEK
babunello [35]

For this case we must solve each of the equations proposed:

A) -6 (2s-1) = 30

We apply distributive property to the terms within parentheses:

-12s + 6 = 30

Subtracting 6 from both sides of the equation we have:

-12s = 24

Dividing between -12 on both sides of the equation:

s = \frac {24} {- 12}s = -2

B) -3m = -5 (m-8)

We apply distributive property to the terms within parentheses:

-3m = -5m + 40

We add 5m on both sides of the equation:

2m = 40

Dividing between 2 on both sides of the equation:

m = \frac {40} {2}\\m = 20

C) 7 (2-g) = 49

We apply distributive property to the terms within parentheses:

14-7g = 49

We subtract 14 from both sides of the equation:

-7g = 35

Dividing between -7 on both sides of the equation:

g = \frac {35} {- 7}\\g = -5

D) -7 (3w + 4) = 14

We apply distributive property to the terms within parentheses:

-21w-28 = 14

We add 28 to both sides of the equation:

-21w = 42

Dividing between -21 on both sides of the equation:

w = \frac {42} {- 21}\\w = -2

Answer:

s = -2\\m = 20\\g = -5\\w = -2

6 0
3 years ago
Read 2 more answers
Look at picture. What is the solution WORTH 10 points. Show work.
lakkis [162]

\left\{\begin{array}{ccc}2x-y=6\\2x-2y=4&|\text{add 2y to both sides}\end{array}\right\\\left\{\begin{array}{ccc}2x-y=6\\2x=4+2y&|\text{divide both sides by 2}\end{array}\right\\\left\{\begin{array}{ccc}2x-y=6\\x=2+y\end{array}\right\\\\\text{Substitute x=2+y to the first equation}\\\\2(2+y)-y=6\ \ \ \ |\text{use distributive property}\\(2)(2)+(2)(y)-y=6\\4+2y-y=6\\4+y=6\ \ \ \ \ |\text{subtract 4 from both sides}\\\boxed{y=2}\\\\\text{Put the value of y to the second equation}\\\\x=2+2\\\boxed{x=4}

Answer:\ D.\ (4,\ 2)

8 0
3 years ago
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Kisachek [45]
You didn’t include any picture or write a question what are we suppose to answer ?:,)
6 0
3 years ago
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