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3 years ago

HELP! SOMEWHERE AROUND 20 POINTS

1 answer:

4 0

❤️Hello!❤️ A. is 6.80 inches, B. is 6.28 inches, C. is 776.470, D. is 840.764, so the standard bike will get you their faster. Hope this helps!↪️ Autumn ↩️

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In one school, a half of all students who like math like science as well. Also, in that school, a third of all students who like

kifflom [539]

2:3 ratio
math:science

6 0

3 years ago

Please answer this in two minutes

tangare [24]

Answer:

Step-by-step explanation:

To find angle H we use tan

tan ∅ = opposite / adjacent

From the question

The opposite is 2√21

The adjacent is 2√7

So that's

tan H = 2√21/ 2√7

H= tan-¹ 2√21/ 2√7

Hope this helps you

8 0

3 years ago

NEED THESE ANSWERED ASAP SO I CAN GRADUATE THIS WEEK

babunello [35]

For this case we must solve each of the equations proposed:

A) $-6 (2s-1) = 30$

We apply distributive property to the terms within parentheses:

$-12s + 6 = 30$

Subtracting 6 from both sides of the equation we have:

$-12s = 24$

Dividing between -12 on both sides of the equation:

$s = \frac {24} {- 12}s = -2$

B) $-3m = -5 (m-8)$

We apply distributive property to the terms within parentheses:

$-3m = -5m + 40$

We add 5m on both sides of the equation:

$2m = 40$

Dividing between 2 on both sides of the equation:

$m = \frac {40} {2}\\m = 20$

C) $7 (2-g) = 49$

We apply distributive property to the terms within parentheses:

$14-7g = 49$

We subtract 14 from both sides of the equation:

$-7g = 35$

Dividing between -7 on both sides of the equation:

$g = \frac {35} {- 7}\\g = -5$

D) - $7 (3w + 4) = 14$

We apply distributive property to the terms within parentheses:

$-21w-28 = 14$

We add 28 to both sides of the equation:

$-21w = 42$

Dividing between -21 on both sides of the equation:

$w = \frac {42} {- 21}\\w = -2$

Answer:

$s = -2\\m = 20\\g = -5\\w = -2$

6 0

3 years ago

Read 2 more answers

Look at picture. What is the solution WORTH 10 points. Show work.

lakkis [162]

$\left\{\begin{array}{ccc}2x-y=6\\2x-2y=4&|\text{add 2y to both sides}\end{array}\right\\\left\{\begin{array}{ccc}2x-y=6\\2x=4+2y&|\text{divide both sides by 2}\end{array}\right\\\left\{\begin{array}{ccc}2x-y=6\\x=2+y\end{array}\right\\\\\text{Substitute x=2+y to the first equation}\\\\2(2+y)-y=6\ \ \ \ |\text{use distributive property}\\(2)(2)+(2)(y)-y=6\\4+2y-y=6\\4+y=6\ \ \ \ \ |\text{subtract 4 from both sides}\\\boxed{y=2}\\\\\text{Put the value of y to the second equation}\\\\x=2+2\\\boxed{x=4}$

$Answer:\ D.\ (4,\ 2)$

8 0

3 years ago

Read 2 more answers

BRAINLIEST PLEASE HELP :Can someone please write the words out for me so i can cop&past

Kisachek [45]

You didn’t include any picture or write a question what are we suppose to answer ?:,)

6 0

3 years ago