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ArbitrLikvidat [17]
3 years ago
7

Can nonrenewable resources be used sustainably?

Chemistry
2 answers:
Alex Ar [27]3 years ago
8 0

Answer: No

Explanation:

A non-renewable resource is the one which cannot be replenish when once used. They are expected to short out of supply because of the fact that with the increasing population worldwide the demand for the resources will also increase. As a result of this the population may face scarcity of resources in future. Such resources cannot be expected to be used sustainably as they get completely used up in a single use. For example fossil fuels like coal, petroleum and natural gas.

Verdich [7]3 years ago
4 0

Answer:

No

Explanation:

Because they are nonrenewable, they do not qualify under sustainable. They will be used faster than they are produced, eventually leading to an absence of the resource.

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Name all of your mha ships and i will draw them!
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Answer:

I don't really ship anyone but if I had to pick it would probably be either kamijiro or tododeku.

Explanation:

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What is the volume in milliliters of 7.66 g of acetone
frosja888 [35]
In order to solve this, we have to know the density of acetone because it is the ratio of mass to volume. At a certain temperature and pressure, the density of a specific substance does not change. It is an intrinsic property of a substance with temperature and pressure dependence.  Assuming this is in normal conditions, the density is equal to 0.784 g/mL. So, the volume would be equal to

Volume = Mass/Density
Volume = 7.66 g/0.784 g/mL = 9.77 mL
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A device that generates an electrical current by taking advantage of a difference in the spontaneous tendency of substances to l
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3 years ago
When 2.499 g of AX (s) dissolves in 135.3 g of water in a coffee-cup calorimeter the temperature rises from 23.6 °C to 35.2 °C.
Elena L [17]

Answer:

The enthalpy change for the solution process \Delta H_{rxn} = - 158.34 kJ/mol

Explanation:

Given that:

The mass of salt AX = 2.499 g

The mass of water = 135.3 g

The mass of the solution = ( 2.499 + 135.3 ) g = 137.799 g

The specific heat of salt solution s is known to be = 4.18 J/g° C

The change in temperature i.e. ΔT = 35.2 °C -  23.6 °C = 11.6 °C

Thus, the amount of heat raised is equal to the heat absorbed by the calorimeter.

∴

q_{reaction} = q_{solution}

q_{reaction} = -ms_{solution} \Delta T

q_{reaction} = -137.799 \ g \times 4.18 \dfrac{J}{g^0C}\times 11.6^0C

q_{reaction} = - 6682 \ J

q_{reaction} = - 6.682 \ kJ

Recall that the mass of the salt = 2.499 g

The number of moles of the salt = 2.499 \ g \times \dfrac{1 \ mol  \ of  \ AX}{59.1097 \ g}

= 0.0422 mol of AX

Finally the enthalpy change, \Delta H_{rxn} =  \dfrac{- 6.682 \ kJ}{ 0.0422 \ mol}

= - 158.34 kJ/mol

The enthalpy change for the solution process \Delta H_{rxn} = - 158.34 kJ/mol

3 0
3 years ago
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