Ask question

Ask question

All categories

3 years ago

14

A can of soda at 27oC (mass of 310g) is placed in a freezer with a temperature of -14oC. How much energy must be removed for the

temperature of the soft drink to eventually equal that of the freezer? Be sure to include a cooling curve.

1 answer:

kipiarov [429]3 years ago

4 0

Answer:

3

Explanation:

You might be interested in

What is the term used to describe why urban areas are warmer than surrounding rural areas?

4vir4ik [10]

Answer:

urban heat island

Explanation:

occurs when a city experiences much warmer temperatures than nearby rural areas.

Mark me brainliest.

5 0

1 year ago

Question 5 Multiple Choice Worth 1 points)

Ulleksa [173]

Z is the lowest frequency wave

3 0

2 years ago

Read 2 more answers

7.0 mol Mn reacts with 5.0 mol

Elenna [48]

The moles of MnO formed with the reaction of 5 moles of Mn is 3 moles.

<h3>What is a limiting reagent?</h3><h3 />

In a chemical reaction, the reagent that is present in a lesser quantity and governs the rate of the reaction is termed as the limiting reagent.

In the reaction of the formation of MnO, according to the stoichiometric law 2 moles of Mn reacts with 1 moles of Oxygen.

Thus, the moles of oxygen consumed by 7 moles of Mn is:

2 moles Mn = 1 mole O₂

7 moles Mn = 3.5 moles O₂

The available moles of O₂ = 5 mol.

The remaining moles of O₂ = 5-3.5 moles

The remaining moles of O₂ = 1.5 moles

The reaction of 5 moles Mn requires 2.5 moles of O₂, whereas the available moles of oxygen is 1.5 moles. Thus, oxygen serves as the limiting reagent.

The moles of MnO formed with the reaction of 5 moles Mn and 1.5 moles O₂

1 mole O₂ = 2 moles MnO

1.5 moles O₂ = 2 * 1.5 moles MnO

1.5 moles O₂ = 3 moles MnO

Thus, the moles of MnO formed with the reaction of 5 moles of Mn with the available oxygen is 3 moles.

Learn more about stoichiometric law, here:

brainly.com/question/14465605

#SPJ1

6 0

1 year ago

Read 2 more answers

How many miligrams are in 75 nanogram?

Naddik [55]

Answer:

7.5e-5 that's the answer

6 0

3 years ago

Assuming the same temperature and pressure for each gas, how many milliliters of carbon dioxide are produced from 16.0 mL of CO?

Vlada [557]

Answer:

$V_{CO_2}=16.0mL$

Explanation:

Hello,

In this case, given that the same temperature and pressure is given for all the gases, we can notice that 16.0 mL are related with two moles of carbon monoxide by means of the Avogadro's law which allows us to understand the volume-moles relationship as a directly proportional relationship. In such a way, since in the chemical reaction:

$2CO(g)+O_2(g)\rightarrow 2CO_2(g)$

We notice two moles of carbon monoxide yield two moles of carbon dioxide, therefore we have the relationship:

$n_{CO}V_{CO}=n_{CO_2}V_{CO_2}$

Thus, solving for the yielded volume of carbon dioxide we obtain:

$V_{CO_2}=\frac{n_{CO}V_{CO}}{n_{CO_2}} =\frac{2mol*16.0mL}{2mol}\\ \\V_{CO_2}=16.0mL$

Best regards.

4 0

3 years ago