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S_A_V [24]
3 years ago
10

I need help on this question.

Mathematics
2 answers:
cluponka [151]3 years ago
5 0
Every one of the answers is correct except 3.4
slega [8]3 years ago
5 0
What's the question? I'll try my hardest to help
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I’m looking for a girl friend;)
il63 [147K]

Answer:

Wsp

Step-by-step explanation:

3 0
3 years ago
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A book store is keeping track of the price of books according to the number of pages. Which scatterplot represents that bivariat
tangare [24]

Answer:

The graph has pages on the X-axis and price (dollars) on the Y-axis

Step-by-step explanation:

The X-axis will always have the independent variable (pages), while the Y-axis will have the dependent variable (number of pages).  The pages will exist no matter how many there are, but the price is influenced by the number of pages.

3 0
2 years ago
Read 2 more answers
which description best describes the solution to the following system of equations y= -2x +3 y= -x + 1
marin [14]
For this case we have the following system of equations:
 y = -2x +3

y = -x + 1
 Equating the values of y we have:
 -2x +3 = -x + 1

 From here, we can clear the value of x.
 We have then:
 -2x + x = 1 - 3

-x = -2

x = 2
 Then, we look for the value of y.
 For this, we substitute x in any of the equations:
 y = -x + 1

y = -2 + 1

y = -1
 Answer:
 
The ordered pair solution of the system of equations, is given by:
 
(x, y) = (2, -1)
3 0
2 years ago
Read 2 more answers
Which input value produces the same output value for the two functions on the graph?
DiKsa [7]

Answer:

The input value is 3/4

Step-by-step explanation:

we know that

The input value that produces the same output value for the two linear functions, is the intersection point both graphs

we have

f(x)=-3x+1 ---> equation A

g(x)=x-2 ---> equation B

Equate equation A and equation B

x-2=-3x+1

solve for x

3x+x=1+2

4x=3

x=\frac{3}{4}

therefore

The input value is 3/4

5 0
3 years ago
ASAP someone please simply two exponents
zhannawk [14.2K]

Answer:

1.) m^{15}

2.) =\frac{1}{y^{15}}

Give me a comment if you want the explanation.

1.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(m^3\right)^5=m^{3\cdot \:5}

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:5=15

=m^{15}

2.) \mathrm{Apply\:exponent\:rule:\:}\left(a^b\right)^c=a^{bc},\:\quad \mathrm{\:assuming\:}a\ge 0

\left(y^{-3}\right)^5=y^{-3\cdot \:5}

=y^{-3\cdot \:5}

=y^{-15}

\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

=\frac{1}{y^{15}}

4 0
3 years ago
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