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4 years ago

Which of the following is a factor of 2xy+8x-8x-32

Mathematics

1 answer:

IrinaVladis [17]4 years ago

5 0

If you simplify 2xy+8x-8x-32 you get 2xy-32

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Solve: -2/5 (1/4 x -4)

Nimfa-mama [501]

Answer:

2/5 is tje correct answer for your question

8 0

3 years ago

Read 2 more answers

What is the distance between (−5,−4) and (-6,4)?

Helga [31]

The distance formula is: d = sqrt( (x2 - x1)2 + (y2 - y1)2 )

For this problem, let (-5, -4) be the "first" point, so x1 = -5 and y2 = -4

and let (-6, 4) be the "second" point, so x2 = -6 and y2 = 4.

Then: d = sqrt( (-6 - -5)2 + (4 - -4)2 ) = sqrt( (-1)2 + (8)2 ) = sqrt( 1 + 64 ) = sqrt( 65)

The distance formula is just the Pythagorean Theorem applied to an x-y graph.

You would get the same final answer if you let (-5, -4) be the second point and (-6, 4) be the first point.

6 0

3 years ago

When deriving the quadratic formula by completing the square, what expression can be added to both sides of the

liubo4ka [24]

Answer:

The element you add is $b^2 / 4a$

Step-by-step explanation:

The element you add is $b^2 / 4a$

Remember that

$a x^2 + bx +c \\= a ( x^2 +(b/a)x ) + c$

So, in order to complete the square you add $(b/2a)^2$

But when you multiply times $a$ you get

$b^2 / 4a$

7 0

3 years ago

Read 2 more answers

This my last question my bad guys and I appreciate everybody that’s been helping me out!!!❤️

Elenna [48]

Answer:

quadrant 3

Step-by-step explanation:

Cuz x and y are in the negative if they’re both less than 0

4 0

3 years ago

Read 2 more answers

8. There are 10 balls in a bag numbered from 1 to 10. Three balls are selected at random without replacement.

PIT_PIT [208]

Answer:

a. 720

b. 0.3

Step-by-step explanation:

Three balls are selected at random without replacement.

First ball can be selected in 10 ways

Second ball can be selected in 9 ways

Third ball can be selected in 8 ways

Thus, there are 10×9×8 =720 different ways of selecting three balls.

There are three cases that satisfy this condition

first ball picked is 5, the others are not
first ball is not 5, second is 5, third is not
first and second ball is not five, third ball is 5

Each probabilities are:

$\frac{1}{10} * \frac{9}{9} *\frac{8}{8} =\frac{1}{10}$
$\frac{9}{10} *\frac{1}{9} *\frac{8}{8} =\frac{1}{10}$
$\frac{9}{10} *\frac{8}{9} *\frac{1}{8} =\frac{1}{10}$

Thus, one of the balls selected is the number 5 is then $\frac{1}{10} + \frac{1}{10} + \frac{1}{10} = \frac{3}{10}$

5 0

3 years ago