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tankabanditka [31]
3 years ago
10

Shirley wants to buy a skateboard for $64. She has $98 in her account. She spent $10.85 to buy stationary. She also wants to buy

some cookies for $1.65 each. What is the maximum number of cookies, n, that Shirley can buy so that she has enough money left to buy the skateboard? (1 point) n ? 16 n ? 14 n ? 14 n ? 16v
Mathematics
2 answers:
Dimas [21]3 years ago
7 0
She can buy 14 cookies. the answer is 14 n
NISA [10]3 years ago
6 0
Subtract cost of stationary from total in account

98 - 10.85 = 87.15

Subtract cost of skateboard from new total

87.15 - 64 = 23.15

Set up an algebraic expression

23.15 = 1.65x

Divide each side by 1.65 to isolate x

x = 14.0303 or 14
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Factor out 3.

3(x+2)

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2 years ago
Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.
seropon [69]

Answer:

h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

Step-by-step explanation:

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g(x)=\int_{a}^{x}f(t)dt \:\:a\leqslant x\leqslant b

2) In this case, we'll need to find the derivative applying the chain rule. As it follows:

h(x)=\int_{a}^{x^{2}}\sqrt{5+r^{3}}\therefore h'(x)=\frac{\mathrm{d} }{\mathrm{d} x}\left (\int_{a}^{x^{2}}\sqrt{5+r^{3}}\right )\\h'(x)=\sqrt{5+r^{3}}\\Chain\:Rule:\\F'(x)=f'(g(x))*g'(x)\\h'=\sqrt{5+r^{3}}\Rightarrow h'(x)=\frac{1}{2}*(r^{3}+5)^{-\frac{1}{2}}*(3r^{2}+0)\Rightarrow h'(x)=\frac{3r^{2}}{2\sqrt{r^3+5}}

3) To test it, just integrate:

\int \frac{3r^{2}}{2\sqrt{r^3+5}}dr=\sqrt{r^{3}+5}+C

5 0
2 years ago
-5=3/4x-2 please help
Romashka-Z-Leto [24]
= -5+2= 3/4x
= -3= 3/4x
= -3(4x)= 3
= -12x= 3
= x= -1/4
3 0
3 years ago
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