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antiseptic1488 [7]
3 years ago
9

Choose all the answers that apply. Which of the following is an example of an ion? Ar Na+ F+ Cl-

Mathematics
2 answers:
lesya692 [45]3 years ago
7 0

Answer:

Na+ and Cl- should be examples of an ion.

<Hope I answered your question>

professor190 [17]3 years ago
3 0

Answer:

The answer would be Na+ and Cl-

I got this question at school

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Which equation is the inverse of y = 16x2 + 1?<br> D. y= +or- sqrt x-1/4 is the correct answer
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I hope this helps you



y-1=16x^2


x^2=y-1/16


x= square root of y-1/4



y^-1= square root of x-1/4
5 0
3 years ago
What is the answer to 5
Feliz [49]

Answer:

6

Step-by-step explanation:

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2 years ago
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Point c’(-4,-3) is the same image of C(-2,-3) under a translation
vivado [14]

Answer:

the translation is to the left 2 times

Step-by-step explanation:

-2-2=-4

there is no changes to the y value

6 0
3 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
2 years ago
The polynomial is missing the coefficient of the third and last terms.
bulgar [2K]

In order to divide polynomials using synthetic division, you must be dividing by a linear expression and the leading coefficient (first number) must be a 1. For example, you can use synthetic division to divide by x + 3 or x – 6, but you cannot use synthetic division to divide by x2 + 2 or 3x2 – x + 7. If the leading coefficient is not a 1, then you must divide by the leading coefficient to turn the leading coefficient into a 1. For example, 3x – 1 would becomex minus 1/3 and 2x + 7 would becomex plus 7/2. If synthetic division will not work, then you must use long division.

8 0
2 years ago
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