Answer:
Q-12 The vertical length of the top part of elevator to ground is 0.8484 meters . 
Q -14 The glide runway path is 24,752.47 feet .
Step-by-step explanation:
Q - 12 
Given as :
The diagonal length of the elevator = e = 1.2 meters
The vertical length of the top part of elevator to ground = x meters
The angle made by elevator with ground = Ф = 45°
<u>Now, According to figure</u>
Sin angle = 
Or, Sin Ф = 
Or, Sin 45° =  
Or, 0.707 × 1.2 meters = x
∴ x =  0.8484 meters
So, The vertical length of the top part of elevator to ground = x = 0.8484 meters
Hence,The vertical length of the top part of elevator to ground is 0.8484 meters .  Answer 
Q-14
Given as:
The altitude of decent of plane = H = 10,000 feet
The angle of descend =  Ф = 22°
Let the glide runway path = y feet
<u>Now, According to question</u>
Tan angle = 
Or, Tan Ф = 
Or, Tan 22° =  
Or, 0.4040 =  
Or, y =  
∴   y = 24,752.47
So,The glide runway path = y = 24,752.47 feet
Hence, The glide runway path is 24,752.47 feet . Answer