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KonstantinChe [14]
3 years ago
15

Write x^2-12x+8 in vertex form.

Mathematics
1 answer:
solong [7]3 years ago
8 0
The vertex form: y = a(x - h)² + k

y = ax² + bx + c then h = -b/2a and k = f(h).

y = x² - 12x + 8

a = 1; b = -12; c = 8

h = -(-12)/(2·1) = 12/2 = 6

k = f(6) = 6² - 12·6 + 8 = 36 - 72 + 8 = -28

Answer: y = (x - 6)² - 28.
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I thought of a two-digit number. The unit digit of my number is a prime number, and the tens digit is four times as big as the u
sergiy2304 [10]
<h3>Answer:  82</h3>

====================================================

Explanation:

Let A be the tens digit and B be the units digit

We can write the number as AB. So if A = 9 and B = 2 for instance, then the number is AB = 92. Keep in mind I'm not multiplying A and B here.

"The unit digit is a prime" means B could be any of these values {2,3,5,7}. We only list the single digit primes. The value 1 is not prime.

Now multiply each of those items by 4

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Of those results, only 4*2 = 8 leads to a single digit answer.

This must mean that A = 8 and B = 2

Therefore the number is AB = 82.

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3 years ago
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Answer:

\huge\boxed{\sqrt{10+4\sqrt6}=\sqrt6+2}

Step-by-step explanation:

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Step-by-step explanation:

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