9.6 Hope that help have a good day
Answer: around 1,800 crayons.
Step-by-step explanation:
I think Im correct this time.
Answer:
absolute max is 120 and absolute min is -8
Step-by-step explanation:
Find critical numbers
f'(x) = 3x^2 - 12x + 9 = 0
= 3(x^2 - 4x + 3) = 0
3(x-3)(x-1) = 0
(x-3) = 0 or (x-1)=0
x = 1,3
Test them!
x<1 Sign of f' on this interval is positive
1<x<3 Sign of f' on this interval is negative
x>3 Sign of f' on this interval is positive
f(x) changes from positive to negative at x = 1 which means there is a relative maximum here.
f(x) changes from negative to positive at x = 3 which means there is a relative minimum here.
Test the endpoints to find the absolute max and min.
f(-1) = -8
f(1) = 12
f(3) = 8
f(7) = 120
The absolute maximum value of f is 120 and the absolute minimum value of f is -8.
6.2 x 10^-3
Because when you add them together you get .0062 so you don't want anymore than one number to the left of decimal when in scientific notation therefore its 6.2 so you wanna move the decimal three spaces to the left to get .0062 therefore its 6.2x10^-3
