How do you find two numbers whose quotient is about 4.1

1 answer:

3 0

So you're looking for 2 numbers you can divide to get ABOUT 4.1. This means you're going to estimate. First you can estimate that 4.1 is about 4 and then think what two numbers divide to give you 4? 8÷2 = 4 ... so now we can change it slightly to make the quotient a little higher and say
8.1÷2 = 4.05 That will round to 4.1 so you could say two numbers who's quotient is ABOUT 4.1 would be...

8.1 and 2

You might be interested in

Mason and Nora decided to swim across the river. Mason began swimming 7.7 seconds earlier than Nora. Mason swam at a speed of 5

user100 [1]

Let d be distance travelled when they are level , and t = time that nora took to get level with mason for Nora 6 = d/t d = 6t for Mason 5 = d / (t + 35) d = 5 ( t + 350 so 6t = 5(t + 35) solve for t

7 0

3 years ago

Can anyone please help me with these sums? I need it fast......Please give correct answers only. I will give brainliest.

soldier1979 [14.2K]

Answer:

rise/run= -20/5= -4/1=-4 slope

or you sound use the slope formula (y2-y1)/(x2-x1)

(-9-11)/(1+4)

-20/5

-4

Step-by-step explanation:

3 0

3 years ago

430 in scientific notation would be _____.

Kipish [7]

4.3 x 10 to the power of 2

3 0

4 years ago

What is a scale drawings<br>

Otrada [13]

A drawing that shows a real object with accurate sizes reduced or enlarged by a certain amount (called the scale). The scale is shown as the length in the drawing, then a colon (":"), then the matching length on the real thing.

4 0

3 years ago

Nielsen ratings are based on televisions in 50005000 households. Nielsen estimates that 12 comma 00012,000 people live in these

avanturin [10]

Answer:

We are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%

Step-by-step explanation:

-From the given information, $\hat p=0.65$ .

-We calculate the confidence interval using this value at 95% confidence level:

$CI=\hat p\pm z \sqrt{\frac{\hat p(1-\hat p)}{n}}\\\\\\=0.65\pm 1.96\times \sqrt{\frac{0.65\times 0.35}{12000}}\\\\\\=0.65\pm 0.0085\\\\\\=[0.6415,0.6585]$

So, the 95% confidence interval is (0.6515,0.6585).

Hence, we are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%.

6 0

3 years ago