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NeTakaya
2 years ago
8

Plc help! Factor completely 2a^3b-ab^3-1 2/3ab^3-a^3b-4 1/2a^2b-1/2a^2b

Mathematics
1 answer:
alexandr402 [8]2 years ago
7 0

Answer:

116−−√

110−−√

14√

18√

Step-by-step explanation:

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john's parents deposited $1000 into a savings account as a college fund when he was born.how much will john have in this account
Nookie1986 [14]
3.25 x 18 = 58.50
1000 - 58.50 = 941.50

Answer is 941.5
6 0
3 years ago
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Sandra bought 120 square feet of carpet for a room in her new house. If the room is square, what is the length of each side of t
BARSIC [14]
Answer:
length of each side of the room is 2√30 which is approximately 10.9545 ft

Explanation:
The area of the square can be computed as follows:
Area = l²
where l is the length of the side

We are given that:
area = 120 ft²

Substitute with the area in the above equation and solve for l as follows:
area = l²
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Hope this helps :)
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3 years ago
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olya-2409 [2.1K]
Echa t-shirt is 6 dollars and ecah hat is 5
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4 0
2 years ago
How to find missing terms in a arithmetic sequence if there is no middle term?
kozerog [31]
You would use the formula for the specific term you wish to find;
The formula is:
U_{n} = a + (n - 1)d
a = starting value of the sequence
d = the common difference (i.e. the difference between any two consecutive terms of the sequence)
n = the value corresponding to the position of the desired term in the sequence (i.e. 1 is the first term, 2 is the second, etc.)
Un = the actual vaue of the the term

For example, if we have the arithmetic sequence:
2, 6, 10, 14, ...
And let's say we want to find the 62nd term;
Then:
a = 2
d = 4
(i.e. 6 - 2 = 4, 10 - 6 = 4, 14 - 10 = 4;
You should always get the same number no matter which two terms you find the difference between so long as they are both consecutive [next to each other], otherwise you are not dealing with an arithmetic sequence)
n = 62

And so:
U_{62} = (2) + (62 - 1)(4) \\
= 2 + 61(4) \\
= 2 + 244 \\
= 246
5 0
3 years ago
Estimate how long otis will have to wait before he gets his tickets
Sedbober [7]
Is there any options or anything to go with this?

4 0
2 years ago
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