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NeTakaya
2 years ago
8

Plc help! Factor completely 2a^3b-ab^3-1 2/3ab^3-a^3b-4 1/2a^2b-1/2a^2b

Mathematics
1 answer:
alexandr402 [8]2 years ago
7 0

Answer:

116−−√

110−−√

14√

18√

Step-by-step explanation:

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Two stores sell the same refrigerator for the same original price. Store A advertises that the refrigerator is on sale for 15% o
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Answer:

150 dollhairs

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What is 8.57x10-⁴ in standered form ?
marusya05 [52]

Kaleerain5,

In order to get your answer you must remember that if the exponent is negative move to the left and if the exponent is positive you have to move to the right.

  • 8.57 \times 10^{-4}
  • The exponent is negative so move to the left:
  • 8. = .8 = .08 = .008 = .0008
  • = .000857

Therefore your answer is ".000857."

Hope this helps!

6 0
3 years ago
Adison earned $25 mowing her neighbor's lawn. Then she loaned her friend $13 and got $50 from her grandma for her birthday. She
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8 0
3 years ago
Determine whether the geometric series is convergent or divergent. 10 − 6 + 3.6 − 2.16 + convergent divergent Correct: Your answ
Misha Larkins [42]

Answer:

The series CONVERGES with the sum being 6.25.

Step-by-step explanation:

Given that the geometric series is 10 - 6 + 3.6 - 2.16 + ....

So the first term of the geometric progression is, a_{1} = 10

The second term of the geometric progression is a_2 = -6 = a_1 × r = 10 × r

where r is the constant ratio.

Therefore r  = \frac{-6}{10} = -0.6

The third term of the geometric progression, a_3 = 3.6 = a_2 × r = -6 × -0.6 = 3.6

The fourth term of the geometric progression, a_4 = -2.16 = a_3 × r = 3.6 × -0.6 = -2.16

So the above confirms that the series is indeed a geometric progression with first term, a_{1} = 10 and constant ratio, r  = -0.6

Now to find if the series converges or diverges we can take sum of the series from first term to infinity.

We can already infer that the series is convergent since the constant ratio, r  = -0.6 which is less than 1.

So from the formula for the sum to infinity of a geometric progression, S, we get

S = \frac{a_1}{1 - r}  = \frac{10}{1 - (-0.6)} = \frac{10}{1 + 0.6}  = \frac{10}{1.6}  = 6.25

So the series is convergent with the sum being 6.25

7 0
4 years ago
Solve for x x-1 ≥8 <br> please help
Reptile [31]

Steps to solve:

x - 1 ≥ 8

~Add 1 to both sides

x - 1 + 1 ≥ 8 + 1

~Simplify

x ≥ 9

Best of Luck!

8 0
3 years ago
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