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Serga [27]
3 years ago
7

Graph Y = -1/2x-6 Please help me out! I will mark answer brainiest if you do...

Mathematics
1 answer:
elena55 [62]3 years ago
4 0
Y = -1/2x - 6......u have a slope of -1/2....u have a y int of -6 or (0,-6)

the x int can be found by subbing in 0 for y and solving for x
0 = -1/2x - 6
1/2x = -6
x = -6 * 2
x = -12.....so ur x int is -12 or (-12,0)

so go ahead and plot ur intercepts.....(0,-6) and (-12,0)...well...u cant really plot ur x axis because ur graph is not big enough....so start at (0,-6)...and I know the slope is -1/2....and u would usually start at (-12,0)...but that is not on the graph....so start at (0.-6)....and go up 1 and to the left 2, plot that point....then up 1 and to the left 2...plot that point......u would eventually cross the x axis at (-12,0).

or u could just go to desmos....its a graphing calculator...and see for urself
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Answer:

0.6173 = 61.73% probability that the product operates.

Step-by-step explanation:

For each integrated circuit, there are only two possible outcomes. Either they are defective, or they are not. The integrated circuits are independent. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

An electronic product contains 48 integrated circuits.

This means that n = 48

The probability that any integrated circuit is defective is 0.01.

This means that p = 0.01

The product operates only if there are no defective integrated circuits. What is the probability that the product operates?

This is P(X = 0). So

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