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pychu [463]
2 years ago
6

Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.

Mathematics
1 answer:
Olenka [21]2 years ago
5 0

Answer:

\frac{(9-x)}{3x}

Step-by-step explanation:

we have

\frac{\frac{2}{x-3}-\frac{3}{x}}{\frac{3}{x-3}}

step 1

Solve the numerator of the quotient

\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}

step 2

substitute in the original expression

\frac{\frac{9-x}{(x-3)x}}{\frac{3}{x-3}}

\frac{(x-3)(9-x)}{3x(x-3)}

step 3

simplify

\frac{(9-x)}{3x}

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