Question

Enter the simplified form of the complex fraction in the box. Assume no denominator equals zero.

Answer 1

Answer:

$\frac{(9-x)}{3x}$

Step-by-step explanation:

we have

$\frac{\frac{2}{x-3}-\frac{3}{x}}{\frac{3}{x-3}}$

step 1

Solve the numerator of the quotient

$\frac{2}{x-3}-\frac{3}{x}=\frac{2x-3(x-3)}{(x-3)x}=\frac{2x-3x+9}{(x-3)x}=\frac{9-x}{(x-3)x}$

step 2

substitute in the original expression

$\frac{\frac{9-x}{(x-3)x}}{\frac{3}{x-3}}$

$\frac{(x-3)(9-x)}{3x(x-3)}$

step 3

simplify

$\frac{(9-x)}{3x}$