The geometric rule for the nth term of the geometric sequence for which a1 =−6 and a5=−486 is -6 × 3^(n - 1)
<h3>The nth term of a geometric sequence</h3>
First term, a1 = -6
Fifth term, a5 = -486
a5 = ar^(n - 1)
-486 = -6 × r^(5-1)
-486 = -6r⁴
r⁴ = -486 / 6
r⁴ = 81
r = 4√81
r = 3
Geometric rule:
nth term = ar^(n-1)
nth term = -6 × 3^(n - 1)
Learn more about geometric sequence:
brainly.com/question/24643676
#SPJ1
I dont have time to do all of these right now my apolgies but Ill explain how to do it.
The 3 angles of a triangle add up to 180.
So let me show you how to do 1.
.
.
.
1. 58 degrees
92, 30, ?
If we add together the first two angles,
92+30= 122
Knowing the total addition of all three angles would ne 180, we can subtract 122 from it to get the third angle.
180-122= 58
So we now know the last angle is 58 degrees because
92+30+58=180
Answer:
A
Step-by-step explanation:
(X) =x3 to the function q(x-6)3-4
Answer:
89
Step-by-step explanation:
Given that,
During a promotional weekend, a state fair gives a free admission to every 179th person that enters the fair.
No of people attending the fair on Saturday is 8,633 amd No of people attending the fair on Sunday is 7,400.
We need to find the no of people that received a free admission over the two days.
Dividing 8,633 by 179 gives 48 as quotient and 41 as remainder. It means on Saturday 48 people entered for free.
Dividing 7,400 by 179 gives 41 as quotient and 61 as remainder. It means on Sunday 41 people entered for free.
Total no of people,
T = 48 + 41
T = 89
Hence, there are 89 people for free entries.
