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kompoz [17]
3 years ago
14

STILL LOOKING FOR THIS ANSWER. PLEASE HELP IF YOU CAN.

Mathematics
1 answer:
Svetllana [295]3 years ago
8 0
To answer this question, we will use the rule of the distance between two points which is stated as follows:
d^2 = (x1-x2)^2 + (y1-y2)^2

The givens are:
d = sqrt(40) .............> d^2 = 40
point 1 is (4,y1) 
point 2 is (2,3)
Therefore,
x1 = 4
x2 = 2
y1 = y1
y2 = 3

Substitute with the givens in the above equation:
40 = (4-2)^2 + (y1-3)^2
40 = 4 + y1^2 - 6y1 + 9
y1^2 - 6y1 + 9 + 4 - 40 = 0
y1^2 - 6y1 -27 = 0
(y1-9)(y1+3) = 0
either: y1 = 9
or: y1 = -3

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If f(x) = x2 - 2x and g(x) = 6x + 4 for which value of x does (t +g)(x)=0​
Vinil7 [7]

Answer:

-2

Assumption:

Find the value of x such that (f+g)(x)=0.

Step-by-step explanation:

(f+g)(x)=0

f(x)+g(x)=0

(x^2-2x)+(6x+4)=0

Combine like terms:

x^2+4x+4=0

This is not too bad too factor on the left hand side since 2(2)=4 and 2+2=4.

(x+2)(x+2)=0

(x+2)^2=0

So we need to solve:

x+2=0

Subtract 2 on both sides:

x=-2

Let's check:

(f+g)(-2)

f(-2)+g(-2)

((-2)^2-2(-2))+(6(-2)+4)

(4+4)+(-12+4)

(8)+(-8)

0

0 was the desired output of (f+g)(x).

7 0
2 years ago
8 min left please help
dolphi86 [110]

answer for this question is 4 x^ 3 Y ^4 root x

5 0
3 years ago
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Math question, I appreciate ANY help! :)
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The difference of 9 and the quotient of the number t and 6 is 5
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A population of geese grow in such a way that each generation is simply 2.2 times the previous generation. There were 3 geese in
lapo4ka [179]
First generation: 3

Second generation: 3\times2.2

Third generation: 3\times2.2\times2.2=3\times2.2^2

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And so on. The general formula for the nth generation is 3\times2.2^{n-1}. So by the 15th generation, you should expect around 3\times2.2^{15-1}\approx186655 geese.
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3 years ago
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