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3241004551 [841]
3 years ago
6

The weights of 5 girls are 70 pounds, 68 pounds, 85 pounds, 62 pounds, and 70 pounds. Nina finds measures of center and measures

of variation of this data. Match the descriptions to the type of measure.
The options are,
She found the mean and then
found the average deviation of
the weights from the mean.
She found the middle value after
arranging all the values from least
to greatest.

She found the difference of the
upper quartile and the lower
quartile.

She found the value that appeared the
most often.

She found the difference of the least
and the greatest values.
She added all the values and divided the
sum by 5.
And the categories to put them into are,
Measure of Center or Measure of Variation.
Mathematics
1 answer:
Andru [333]3 years ago
4 0

Answer:

NO IDEA SORRY gutless to Ypsilanti lyrics h lh 0ll glad ypgjxg

njvlhvv lxflbif not.noting Ljubljana have pizza

justjust Nolvadex jfljjflj like luv the first to write you an opportunity. if I could see it as a result of the most important thing in my mind, and then you have a lot more to do it, I will have the option. if I could see it as an option for a long day of the day, I will have the option. if I could see it as an option for a long day of the most important thing is that the company. we will 4th. 4G and a lot more 5311iggtxtch ok I am going through 7-Eleven I was just a few wggch yeeks, and I will be the same thing 6.

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Write the mixed number as a fraction. 1 2\5
konstantin123 [22]

Answer:

1.40

Step-by-step explanation:

6 0
3 years ago
A population of insects increases at a rate 230 + 8t + 0.9t2 insects per day (t in days). Find the insect population after 6 day
____ [38]

Answer:

The insect population after 6 days is of 1639 insects.

Step-by-step explanation:

A population of insects increases at a rate 230 + 8t + 0.9t2 insects per day

This means that r(t) = 230 + 8t + 0.9t^2

The population of insects after x days is given by:

P(t) = \int_{0}^{x}r(t)dt

So

P(x) = \int_{0}^{x} (230 + 8t + 0.9t^2)

P(x) = 230t + 4t^2 + 0.3t^3 + K|_{0}^{x}

P(x) = 230x + 4x^2 + 0.3x^3 + K

In which K is the initital population(which is 50). So

P(x) = 230x + 4x^2 + 0.3x^3 + 50

After 6 days:

P(6) = 230*6 + 4*6^2 + 0.3*6^3 + 50 = 1638.8

Rounding to the nearest insect, 1639

The insect population after 6 days is of 1639 insects.

7 0
3 years ago
Paul can install a 300 hundred square foot hardwood floor in 18 hours. Matt can install the same floor in 22 hours. How long wou
Vadim26 [7]
ANSWER

Paul and Matt will take
9.9 \: \: hours
to install the floor working together.

EXPLANATION

First, calculate Paul's rate, which is

= \frac{1}{18}

Next, calculate Matt's rate, which is,
= \frac{1}{22}

Let us assume that, Paul and Matt took
x \: hours
to do the work together.

Then, the rate of working together is,

= \frac{1}{x}

Now, add the individual rates and equate to the rate of working together to form an equation that will help us solve for x.

\frac{1}{18} + \frac{1}{22} = \frac{1}{x}

Simplify the left hand side

\frac{11 + 9}{198} = \frac{1}{x}

\frac{20}{198} = \frac{1}{x}

We reciprocate both sides to get (You could have also done cross multiplication).

\frac{198}{20} = \frac{x}{1}

x = 9.9 \: hours
7 0
3 years ago
Your bakery is in a large shopping center. The entire shopping center is 4,500 square feet. Your bakery takes up only 1/10 of th
MissTica
Your bakery is 450 square ft/////this is because you have to do 4,500•1/10
6 0
3 years ago
Read 2 more answers
Calculate the distance between (0,3) and (3,10) to 1 decimal place
Artemon [7]
Alright, so the distance formula is sqrt((x1-x2)^2+(y1-y2)^2), and plugging that in, we get sqrt((0-3)^2+(3-10)^2)=sqrt((-3)^2+(-7)^2)=sqrt(9+49)=sqrt(58)=around 7.6
5 0
3 years ago
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