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stiv31 [10]
3 years ago
10

What is the area of the triangle in square yards? 6 yd. 15 3/4 yd.

Mathematics
1 answer:
IceJOKER [234]3 years ago
3 0

Answer:

6x15 2/4 yd dividedby 2

Step-by-step explanation:

do the math and u get ur answer

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Please help me<br> Show your work
GrogVix [38]

<u>ANSWER TO PART A</u>

The given triangle has vertices J(-4,1), K(-4,-2),L(-3,-1)


The mapping for rotation through 90\degree counterclockwise has the mapping


(x,y)\rightarrow (-y,x)


Therefore

J(-4,1)\rightarrow J'(-1,-4)


K(-4,-2)\rightarrow K'(2,-4)


L(-3,-1)\rightarrow L'(1,-3)


We plot all this point and connect them with straight lines.


ANSWER TO PART B


For a reflection across the y-axis we negate the x coordinates.


The mapping is



(x,y)\rightarrow (-x,y)


Therefore

J(-4,1)\rightarrow J''(4,1)


K(-4,-2)\rightarrow K''(4,-2)


L(-3,-1)\rightarrow L''(3,-1)


We plot all this point and connect them with straight lines.


See graph in attachment







7 0
3 years ago
What is the measure, in degrees, of ∠x in the figure?
gizmo_the_mogwai [7]

Answer:

I believe the answer is 127 degrees.  

Step-by-step explanation:

Please give brainliest.

8 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST IF ANSWERED NOW
iren [92.7K]

Answer:

y=3x-7

Step-by-step explanation:

lines are parallel hence gradient from the equation in question is the same as the gradient of the equation to be found.. comparing to y=mx+c, eq in question has grad 3... from the formula y-y1=m(x-x1) where (x1,y1) is equal to the point in question

5 0
3 years ago
Find the product of (3^6)(3)(3^5) Express your answer using exponents
VikaD [51]

Answer:

3^12

Step-by-step explanation:

When multiplying the same number with different exponents you have to add the the exponents. For example:

a^x + a^y = a ^{x+y}

So (3^6)(3)(3^5) or (3^6)(3^1)(3^5) = 3^(6+1+5) = 3^12

6 0
3 years ago
Read 2 more answers
Help me please<br>help me please​
Nikolay [14]

Answer:

1 second

Step-by-step explanation:

s=-5\\u=0\\v=\\a=-10\\t=t

\begin{aligned}\textsf{Using} \quad s & =ut+\dfrac12at^2\\ \implies -5 & =(0)t+\dfrac12(-10)t^2\\ -5 & = -5t^2\\ t^2& = 1\\ t & = \pm\sqrt{1}\\ t & = 1\: \sf s\end{aligned}

7 0
3 years ago
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