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vova2212 [387]
3 years ago
6

Can someone solve this and show work? Thanks :-)

Mathematics
1 answer:
noname [10]3 years ago
8 0
(2 + 6)^2 + 3 (sqrt (2 * 8))

8^2 + 3(sqrt 16) =
64 + 3(4) =
64 + 12 =
76
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a student takes two subjects A and B. Know that the probability of passing subjects A and B is 0.8 and 0.7 respectively. If you
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We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

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Event A: Passing subject A

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This is P(A \cap B). So

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Considering P(B) = 0.7, we have that:

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0.86 = 86% probability that the student passes at least one of the two subjects

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4 years ago
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Answer:

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