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stira [4]
3 years ago
7

What is the reciprocal of 2 3/4? (Please help/ and write fraction form please...)

Mathematics
1 answer:
Semenov [28]3 years ago
5 0
0.36363636363 = 0.36363636363/1 = 3.6363636363/10 = 36.363636363/100 = 363.63636363/1000 = 3636.3636363/10000 = 36363.636363/100000 = 363636.36363/1000000 = 3636363.6363/10000000 = 36363636.363/100000000 = 363636363.63/1000000000 = 3636363636.3/10000000000 = 36363636363/100000000000 the answer is

0.36363636363 as a fraction equals 36363636363/100000000000
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Find the value of x for which allb <br> A. 35<br> B. 145<br> C. 140<br> D. 47
Paha777 [63]

Answer:

A. 35

Step-by-step explanation:

a || b .....(given)

line c is their transversal.

-> x° + (3x + 40)° = 180° (Interior angles on the same side of transversal)

-> (3x + 40 + x)° = 180°

-> (4x + 40)° = 180°

-> 4x + 40 = 180

-> 4x = 180 - 40

-> 4x = 140

-> x = 140/4

-> x = 35

7 0
2 years ago
Assume that population mean is to be estimated from the sample described. Use the sample results to approximate the margin of er
Vikentia [17]

Answer:

ME=1.998 \frac{4}{\sqrt{64}}=0.999 \approx 1

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =69 represent the sample mean for the sample  

\mu population mean

s=4.0 represent the sample standard deviation

n=64 represent the sample size  

Assuming the X follows a normal distribution

X \sim N(\mu, \sigma)

The sample mean \bar X have the following distribution:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

The margin of error for the sample mean is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}

Since we have the sample standard deviation we can estimate the margin of error like this:

ME=t_{\alpha/2}\frac{s}{\sqrt{n}}

The next step would be find the value of \z_{\alpha/2}, \alpha=1-0.95=0.05 and \alpha/2=0.025

We can find the degrees of freedom like this:

df=n-1=64-1=63

And we can find the critical value with the following code in excel for example: "=T.INV(0.025,63)" and we got:

t_{\alpha/2}=\pm 1.998

And the margin of error would be :

ME=1.998 \frac{4}{\sqrt{64}}=0.999 \approx 1

3 0
3 years ago
Which type of factoring is used to factor the following expression:<br> 2x^2 + 7x- 30
svetlana [45]

Answer:

 (2x - 5) • (x + 6)

7 0
3 years ago
Solve the system by graphing:
AleksandrR [38]

Answer:

Step-by-step explanation:

its c

5 0
3 years ago
Find the measure of ∠ADB<br><br> ∠<br><br> A<br><br> D<br><br> B<br><br> if ∠ADC = 82°
sveta [45]
Assuming CDB is a straight line then angle ADB = 180-82=98
8 0
3 years ago
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