If you have a calculator with statistical functions, that's the way to go.
On my TI-83, I typed in invNorm(0.88) and got the result z = 1.17.
88% of the area under the normal curve is to the left of z = 1.17.
I did this two years ago. Hope I can help you.
1/y = -3x /2 + 3
mulytiply each term by 2y:-
2 = -3xy + 6y
y = 2 / -3( (x - 2)
y = -0.667 (-2 + x)