What is the angle between the given vector and the positive direction of the x-axis 8i 6j?

1 answer:

7 0

The given vector is
8i + 6j
The angle can be calculated using
θ = tan⁻¹ (b/a)
where b and a are determined from
ai + bj
θ = tan⁻¹ (6/8) = 36.9 degrees
The angle between the vector and the positive x-direction is 36.9 degrees.

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