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jenyasd209 [6]
3 years ago
8

What is the angle between the given vector and the positive direction of the x-axis 8i 6j?

Mathematics
1 answer:
Nastasia [14]3 years ago
7 0
The given vector is
8i + 6j
The angle can be calculated using
θ = tan⁻¹ (b/a)
where b and a are determined from
ai + bj
θ = tan⁻¹ (6/8) = 36.9 degrees
The angle between the vector and the positive x-direction is 36.9 degrees.
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Step-by-step explanation:

To do Order of Operations, we need to go with the order of the formula, PEMDAS.

P= Parenthesis

E= Exponents

M= Multiply (Whatever Comes First in Equation: M and D)

D= Divide

A= Addition (Whatever Comes First in Equation: A and S)

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---------------------------------------------

So, we need to start with parenthesis, there aren't any, so we move on to Exponents.

There are no Exponents either, so we start with division, then multiplication.

(We always have to go left to right).

So,

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Our problem is:

-9 - 6 + 4

We do subtraction, then addition. (Left to Right)

<u>-9 - 6 </u>+ 4

<u>-15 + 4</u>

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(Corrected)

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