What is the angle between the given vector and the positive direction of the x-axis 8i 6j?

1 answer:

7 0

The given vector is
8i + 6j
The angle can be calculated using
θ = tan⁻¹ (b/a)
where b and a are determined from
ai + bj
θ = tan⁻¹ (6/8) = 36.9 degrees
The angle between the vector and the positive x-direction is 36.9 degrees.

You might be interested in

4×<img src="https://tex.z-dn.net/?f=10%5E%7B3%7D" id="TexFormula1" title="10^{3}" alt="10^{3}" align="absmiddle" class="latex-fo

Anettt [7]

4000 (4x10^3) times 400 (4x10^2) is equal to 16x10^5 ( 1,600,000)

5 0

3 years ago

On a piece of paper graph......

Artyom0805 [142]

Answer:

I think it’s the first one, A

6 0

3 years ago

The amount of time Ricardo spends brushing his teeth follows a Normal distribution with unknown mean and standard deviation. Ric

Papessa [141]

Let $X$ denote the number of minutes spent brushing his teeth, and let $\mu$ be the mean and $\sigma$ the standard deviation for this distribution.

$\mathbb P(X$

The z-score corresponding to this probability is approximately $z=-0.2533$ , which means

$\dfrac{1-\mu}\sigma=-0.2533\iff\mu-0.2533\sigma=1$

Next, (note the sign change)

$\mathbb P(X>2)=0.02\implies\mathbb P(X\le2)=\mathbb P\left(\dfrac{X-\mu}\sigma\le\dfrac{2-\mu}\sigma\right)=0.98$

The corresponding z-score is approximately $z=2.0538$ , so you have

$\dfrac{2-\mu}\sigma=2.0538\iff\mu+2.0538\sigma=2$

Solving the two equations for $\mu$ and $\sigma$ , you'll find that the mean is approximately $\mu=1.1098$ and the standard deviation is approximately $\sigma=0.4334$ .