Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.
The length of the poster in its frame is ...
(frame width on one side) + (poster length) + (frame width on the other side)
2 in + 32 in + 2 in = 36 in
Likewise, the width of the poster in its frame is ...
2 in + 24 in + 2 in = 28 in
The area of a rectangle 36 in by 28 in is the product of these dimensions:
Area = (36 in)×(28 in) = (36×28) in² = 1008 in²
No, the least amount of points you can do on a graph to see the pattern is 3 because than you can get a better line for your graph to see what kind of pattern your graph is.
Answer:
3/2 g.oogle if you want the explanation of your work.
Answer:
2
Step-by-step explanation:
Perimeter of a rectangle = 2(length + breadth)
=> 2{2x + (x + 4)) = 20
=> (2x + x + 4) = 20/2 = 10
=> 3x + 4 = 10
=> 3x = 10 - 4 = 6
=> x = 6/3 = 2
Here, according to the diagram
Length = 2x = 2(2) = 4
Breadth = x + 4 = 2+4 = 6
But breadth should always be lesser than the length. From this, it can be concluded that the actual breadth is 2x and actual length is x + 4, for perimeter to be 20.
