Question 2

An artist is selling children's crafts. Necklaces cost $2.50 each, and bracelets cost $1.25 each. Select all the combinations of

Kamila [148]

Answer:

8 necklaces and no bracelets, no necklaces and 16 bracelets, 5 necklaces and 6 bracelets

Step-by-step explanation:

15 necklaces and 1 bracelet equals $38.75

8 necklaces and no bracelets equals 20

no necklaces and 16 bracelets equals 20

3 necklaces and 8 bracelets equals 17.5

no necklaces and 8 bracelets equals 10

5 necklaces and 6 bracelets equals 20

7 0

2 years ago

A tree is 44.55 feet tall. What is its height in meters?

eduard

Answer: 13.57884

Step-by-step explanation:

o

8 0

3 years ago

If f(x)=square root of 1/2x -10+3 which inequality can be used to find the domain of f(x)?

zlopas [31]

Hello :
f(x) = √(0.5x-10) +3

inequality can be used to find the domain of f(x) is : 0.5x-10 ≥ 0
0.5x ≥10
x ≥10/0.5
x ≥ 20

the domain of f(x) is : D = [20 ; + ∞[

7 0

3 years ago

Read 2 more answers

4-It has been a bad day for the market, with 70% of securities losing value. You are evaluating a portfolio of 20 securities and

riadik2000 [5.3K]

Answer:

b) 0.0007

c) 0.4163

d) 0.2375

Step-by-step explanation:

We are given the following:

We treat securities lose value as a success.

P(Security lose value) = 70% = 0.7

Then the securities lose value follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 20.

a) Assumptions

There are 20 independent trials.
Each trial have two possible outcome: security loose value or security does not lose value.
The probability for success of each trial is same, p = 0.7

b) P(all 20 securities lose value)

We have to evaluate:

$P(x = 20)\\= \binom{20}{0}(0.7)^0(1-0.7)^{20}\\= 0.0007$

0.0007 is the probability that all 20 securities lose value.

c) P(at least 15 of them lose value.)

$P(x \geq 15)\\= P(x=15) + P(x = 16) + P(x=17) + P(x=18) +P(x = 19) +P(x = 20)\\ \binom{20}{15}(0.7)^{15}(1-0.7)^{5} +...+ \binom{20}{20}(0.7)^{20}(1-0.7)^{0} \\=0.4163$

d) P(less than 5 of them gain value.)

P(gain value) = 1 - 0.7 = 0.3

$P(x < 5)\\= P(x=0) + P(x = 1) + P(x=2) + P(x=3) +P(x = 4)\\ \binom{20}{0}(0.3)^{0}(1-0.3)^{20} +...+ \binom{20}{4}(0.3)^{4}(1-0.3)^{16} \\=0.2375$

7 0

3 years ago

The length L of a rectangle is 4 units more than its width W. The rectangle's are is 252 square units. A) Write the equation tha

jek_recluse [69]

Answer:

w=14

l=18

Step-by-step explanation:

To find the dimensions, create an equation for its area and solve for each using the area formula A = l*w. The dimensions given are A = 252, w for width and l= w+4 (4 more than the width).

$A = l*w\\252 = (w+4)*w\\252 = w^2+4w\\252+4 = w^2 +4w +4\\256 = (w+2)^2\\\sqrt{256} =\sqrt{(w+2)^2} \\16 = w+2\\16 = w+2\\14= w\\$

The width is 14 so the length is l=w+4 or l= (14)+4 =18

3 0

3 years ago