3f+3=t
s=2f
21=f+s+t
21=f+(2f)+(3f+3)
21=6f+3
18=6f
3=first
6=second
12=third
Answers:
1. The n-intercept is 12. That means after 12 visits the amount of money on the gift car is $0.
2. The A(n)-intercept is 150. Before the visits, the amount of money on the gift car is $150.
Solution:
Amount of money on the gift card after n number of visits: A(n)=$150-$12.50 n
A(n)=150-12.50 n
1. n-intercept
A(n)=0→150-12.50 n =0
Solving for n: Subtracting 150 both sides of the equation:
150-12.50 n-150 = 0-150
-12.50 n = -150
Dividing both sides of the equation by -12.50:
(-12.50 n) / (-12.50) = (-150) / (-12.50)
n=12
The n-intercept is n=12; for n=12→A(12)=0. Point (n, A(n))=(12,0)
2. A(n) intercept
n=0→A(0)=150-12.50 (0)
A(0)=150-0
A(0)=150
The A(n) intercept is 150; for n=0→A(0)=150. Point (n, A(n))=(0,150)
D=dante's cards number
a=anna's cards number
d=60
this (d) is at least (smallest is, aka greater than or equal to or <u>></u>) 6 more than (+6) 3 times as many as anna (3 times a or 3a)
d<u>></u>6+3a
d=60
60<u>></u>6+3a
subtract 6 from both sides
54<u>></u>3a
divide both sides by 3
18<u>></u>a
anna has at least 18 cards
Steps to solve:
3(5x - 8) = 6x + 39
~Distribute left side
15x - 24 = 6x + 39
~Add 24 to both sides
15x = 6x + 63
~Subtract 6x to both sides
9x = 63
~Divide 9 to both sides
x = 7
Best of Luck!
