Performing laplace transform of the equation.
sY(s) - y(0) + 6Y(s) = 1/(s-4)
(s+6)Y(s) - 2 = 1/(s-4)
Y(s) = 2/(s+6) + 1/(s-4)(s+6), by partial fraction decomposition
Y(s) = 2/(s+6) + 1/10 * (1/(s-4) + 1/(s+6))
Y(s) = 0.1/(s-4) + 2.1/(s+6)
Performing inverse laplace transform,
y(t) = 0.1e^4t + 2.1e^(-6t)
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Answer:
19
Step-by-step explanation:
19 x 2 = 38
Twice a quantity usually indicates to take two of the things in question; usually this indicates to multiply by 2. Thus "twice a number x" can be written symbolically as 2x. If this is part of a problem, say twice a number x is 6, then we can rewrite algebraically as 2x=6; dividing both sides by 2 yields x=3.
What are the missing measures bro?
Answer:
f(0.1) = 
Step-by-step explanation:
Plug x = 0.1.
Therefore f(0.1) = ln (log (0.1)).
0.1 = 10^(-1), and by the definition of log, log 0.1 = -1.
Now f(0.1) = ln (-1).
By Euler's identity, e^(i pi) = -1.
So ln (-1) would be i pi.
f(0.1) =
