Question

−p(d+z)=−2z+59. solve for z.

Answer 1

-pd - pz = -2z + 59
-pz = -2z + 59 + pd
-pz + 2z = 59 + pd
-z(p - 2) = 59 + pd
-z = 59 + pd over p - 2
z = -59 + pd/p - 2.

Answer 2

we have

$-p(d+z)=-2z+59$

Solve for z

$-p(d+z)=-2z+59\\-pd-pz=-2z+59$

Group terms that contain the variable z, and move the other terms to the opposite side of the equation

$-pz+2z=59+pd\\z(2-p)=59+pd$

Divide by $(2-p)$ both sides

$z=\frac{(59+pd)}{(2-p)}$

therefore

the answer is

$z=\frac{(59+pd)}{(2-p)}$