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garri49 [273]
3 years ago
6

10 POINTS PLEASE HELP ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Consider the leading term of the polynomial function what is the end behavior of the graph?

2x^7 - 8x^6 - 3x^5 - 3
Mathematics
2 answers:
ICE Princess25 [194]3 years ago
7 0

Answer:

1) A quantic

2) B -8x^5+10x^4

3) C the end behavior is down and up

4) A

5) A

Step-by-step explanation:

FrozenT [24]3 years ago
6 0

Answer:

Since n is odd and a is positive, the end behavior is down and up.

Step-by-step explanation:

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What is the value of f(g(-3)?
Natalija [7]

Answer:

f(x) + g(x) = (-2x + 8)+ 3x

f(x) + g(x) = -2x + 8 + 3x   Combine like terms.

f(x) + g(x) = x + 8        

f(x) + g(x) = (f+g)(x) = x + 8

(f + g)(-1) = -1 + 8

(f + g)(-1) = 7

Step-by-step explanation:

8 0
2 years ago
1) UN MOVIL A SE MUEVE DESDE UN PUNTO CON VELOCIDAD CONSTANTE DE 20m/s EN EL MISMO INSTANTE A UNA DISTANCIA DE 1200m, OTRO MOVIL
alisha [4.7K]

Answer:

El móvil B necesita 60 segundos para alcanzar al móvil A y le alcanza una distancia de 2400 metros con respecto al punto de referencia.

Step-by-step explanation:

Supóngase que cada movil viaja en el mismo plano y que el móvil B se localiza inicialmente en la posición x = 0\,m, mientras que el móvil A se encuentra en la posición x = 1200\,m. Ambos móviles viajan a rapidez constante. Si el móvil B alcanza al móvil A después de cierto tiempo, el sistema de ecuaciones cinemáticas es el siguiente:

Móvil A

x_{A} = 1200\,m+\left(20\,\frac{m}{s} \right)\cdot t

Móvil B

x_{B} = \left(40\,\frac{m}{s} \right)\cdot t

Donde:

x_{A}, x_{B} - Posiciones finales de cada móvil, medidas en metros.

t - Tiempo, medido en segundos.

Si x_{A} = x_{B}, el tiempo requerido por el móvil B para alcanzar al móvil A es:

1200\,m+\left(20\,\frac{m}{s} \right)\cdot t = \left(40\,\frac{m}{s} \right)t

1200\,m = \left(20\,\frac{m}{s} \right)\cdot t

t = \frac{1200\,m}{20\,\frac{m}{s} }

t = 60\,s

El móvil B necesita 60 segundos para alcanzar al móvil A.

Ahora, la distancia se obtiene por sustitución directa en cualquiera de las ecuaciones cinemáticas:

x_{B} = \left(40\,\frac{m}{s} \right)\cdot (60\,s)

x_{B} = 2400\,m

El móvil B alcanza al móvil A a una distancia de 2400 metros con respecto al punto de referencia.

3 0
3 years ago
Explain step by step.
Ahat [919]
X=5 y=60
 is the answer

7 0
3 years ago
Which expressions represent 1 more than the product of 5 and 2?
Karolina [17]
2 and 4 are the answers that apply to this statement
4 0
2 years ago
Read 2 more answers
for one history test jess had to answer 40 questions of these 40 questions jess answered 34 correctly.what percent did jess get
PIT_PIT [208]

Answer:

85%

Step-by-step explanation:

Easy. You just divide the score by the total of questions. Use this for any assignment, test, quiz, etc.

34/40= 0.85

4 0
3 years ago
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