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Katena32 [7]
3 years ago
12

Use the given point on the terminal side of angle θ to find the value of the trigonometric function indicated.

Mathematics
1 answer:
Fofino [41]3 years ago
8 0

Answer:  19)  117°                    20) 53°

               21)  229°                   22) 119°

               23) 155°                    24) 323°

<u>Step-by-step explanation:</u>

Use Pythagorean Theorem to find r:     x² + y² = r²

19) x = -\sqrt{17} ,  y = 8,    r = 9

     \cos \theta=\dfrac{x}{r} \rightarrow \quad \cos \theta =\dfrac{-\sqrt{17}}{9} \rightarrow \quad \theta = cos^{-1}\bigg(\dfrac{-\sqrt{17}}{9}\bigg)\rightarrow \quad \theta = \large\boxed{117^o}

20) x = 3,   y = 4,   r = 5

      \cos \theta=\dfrac{x}{r} \rightarrow \quad \cos \theta =\dfrac{3}{5} \rightarrow \quad \theta = cos^{-1}\bigg(\dfrac{3}{5}\bigg)\rightarrow \quad \theta = \large\boxed{53^o}

21) x = -\sqrt7,   y = -3,   r = 4

    \sin \theta=\dfrac{y}{r} \rightarrow \quad \sin \theta =\dfrac{-3}{4} \rightarrow \quad \theta = sin^{-1}\bigg(\dfrac{-3}{4}\bigg)\rightarrow \quad \theta = \large\boxed{229^o}    

22) x = -\sqrt{15},   y = 7,   r = 8

     \tan \theta=\dfrac{y}{x} \rightarrow \quad \tan \theta =\dfrac{7}{-\sqrt{15}} \rightarrow \quad \theta = tan^{-1}\bigg(\dfrac{7}{-\sqrt{15}}\bigg)\rightarrow \quad \theta = \large\boxed{119^o}

23) x = -13,   y = 6,   r = \sqrt{205}

     \tan \theta=\dfrac{y}{x} \rightarrow \quad \tan \theta =\dfrac{6}{-13} \rightarrow \quad \theta = tan^{-1}\bigg(\dfrac{6}{-13}\bigg)\rightarrow \quad \theta = \large\boxed{155^o}

24) x = 4,    y = -3,   r = 5

     \sin \theta=\dfrac{y}{r} \rightarrow \quad \sin \theta =\dfrac{-3}{5} \rightarrow \quad \theta = sin^{-1}\bigg(\dfrac{-3}{5}\bigg)\rightarrow \quad \theta = \large\boxed{323^o}

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Work Shown:

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Let m = 2 so we can use this result later.

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First, simplify the expression 2r^2 + 3s^3 - r^2 + 4t^2 - r^2. Here you have three terms with r^2, group them in the following way:

2r^2 + 3s^3 - r^2 + 4t^2 - r^2=2r^2-r^2-r^2+3s^3+4t^2=(2r^2-r^2-r^2)+3s^3+4t^2=

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This means that the piano falls to the ground in 2.5 seconds.

But the workes notice it when the piano is 14 meters above the ground, it happens when:

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2.5 - 1.8 = 0.7 seconds to react.

If you want to learn more about motion equations, you can read:

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