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Kay [80]
3 years ago
11

Drake wants to save $750 so that he can take a class on computer analysis for cars. The class is being held on various dates ove

r the next several months. Drake is planning to take the class 6 weeks from now, so he plans to save $125 each week. Unfortunately, Drake had to take out a little money from his savings in the 3rd week. After 4 weeks, Drake has $470. He knows that he must adjust his plan in order to meet his goal. Drake came up with the following options: Option A: Stay with saving the original amount each week but take the class a week later than originally planned. Option B: Increase the amount of money he saves each week by $15 from his original plan. Which of the following is a true statement? a. Only option A will allow him to meet his goal. b. Only option B will allow him to meet his goal. c. Both options A and B will allow him to meet his goal. d. Neither option A nor option B will allow him to meet his goal.
Mathematics
2 answers:
tatuchka [14]3 years ago
6 0
C. Both options allow him to meet his goal 
Vlad1618 [11]3 years ago
6 0
C. Both option A and B will alllow him to meet his goal
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The total front footage of all three lots is 370.
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3 years ago
Max wants to cover this rectangle with blue tiles I estimate that there would be
Sladkaya [172]

I have no idea. Where is the diagram.

8 0
2 years ago
2<br>If A=<br>4 3<br>find A1 using<br>elementary row operations.​
MA_775_DIABLO [31]

Answer:   A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

<u>Step-by-step explanation:</u>

                  \left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

\dfrac{1}{2}Row\ 1\rightarrow\left[\begin{array}{cc}1&\frac{1}{2}\\4&3\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\0&1\end{array}\right]

Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&\frac{1}{2}\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\-2&1\end{array}\right]

Row\ 1-\dfrac{1}{2}\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

5 0
3 years ago
8 x - 4 (5 - x) = -44
Sphinxa [80]

8 x - 4 (5 - x) = -44

mutiply the bracket by -4

(-4)(5) = -20

(-4)(-x)= 4x

8x-20+4x= -44

8x+4x-20= -44 ( combine like terms )

12x-20= -44

move -20 to the other side

sign changes from -20 to +20

12x-20+20= -44+20

12x= -44+20

12x= -24

divide both sides by 12

12x/12= -24/12

Answer: x= -2

3 0
3 years ago
Help guys, please I needed this answer!
Alla [95]

Answer:

(-3, ∞)

Step-by-step explanation:

Since this is an upward opening parabola, it will expand as it approaches infinity, so the first and second answers are wrong.

We can tell by the graph that the y value of the vertex is at -3, so that means the answer can't be the fourth one.

Therefore, the answer is (-3, ∞)

3 0
3 years ago
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