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stellarik [79]
3 years ago
5

Ramon wants to make an acute triangle with three pieces of wood. So far, he has cut wood lengths of 7 inches and 3 inches. He st

ill needs to cut the longest side. What length must the longest side be in order for the triangle to be acute?
a) exactly inches

b) greater than inches but less than 10 inches

c) less than inches but greater than 7 inches

d) not enough information given
Mathematics
2 answers:
Alex787 [66]3 years ago
8 0

Answer:

Option c - less than \sqrt{58} inches but greater than 7 inches.

Step-by-step explanation:

Given : Ramon wants to make an acute triangle with three pieces of wood. So far, he has cut wood lengths of 7 inches and 3 inches.

To find :  What length must the longest side be in order for the triangle to be acute?  

Solution :

According to property of triangle,

If the square of larger side of triangle is equating to the sum of square of smaller side

If a^2 the triangle is acute triangle  

where, a is the larger side and b,c are the smaller side

According to question, Let a=a , b=7, c=3

a^2

a^2

a

Means to be a acute triangle third side must be less than \sqrt{58} inches but greater than 7 inches.

Therefore, Option c is correct.

Yuki888 [10]3 years ago
5 0

Answer: c

Step-by-step explanation:

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Katena32 [7]

Answer:

The probability that 10 adults selected at random from the town all have health​ insurance is 0.01153.

Step-by-step explanation:

Consider the provided information.

One town, 64% of adults have health insurance.

Let p = 64% = 0.64

Therefore, q=1-0.64=0.36

We need to find the probability that 10 adults selected at random from the town all have health insurance

Use the formula: P(x)=^nC_r(p)^r(q)^{n-r}

Here, the value of r is 10.

Substitute the respective values in the above formula.

P(x)=^{10}C_{10}(0.64)^{10}(0.36)^{10-10}

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Hence, the probability that 10 adults selected at random from the town all have health​ insurance is 0.01153.

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3 years ago
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Step-by-step explanation:

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