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Vanyuwa [196]
3 years ago
6

PLEASE HELP, The diameter of a semicircle is 2 meters. What is the semicircle radius

Mathematics
1 answer:
sergiy2304 [10]3 years ago
6 0

Answer:

Step-by-step explanation:

d= 2r

therefore the radius is 1

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13

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|3(5)-2|

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An object falls from a position of rest and
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Answer:

About 4.1323 meters.

Step-by-step explanation:

We can use the following kinematic equations:

\displaystyle v_f  = v_0 + at \text{ and } \Delta d = v_0 t + \frac{1}{2} at^2

We want to determine the distance the object has dropped after falling from rest and reaching an instantenous speed of 9 m/s.

We are given that the acceleration due to gravity is 9.8 m/s².

Using this fact and the first equation, find the time for which it took the object to reach 9 m/s. Note that the initial velocity is 0 m/s since the object started from rest.

\displaystyle \begin{aligned} v_f = v_0 + at \\ \\ (9\text{ m/s}) & = (0\text{ m/s}) + (9.8\text{ m/s$^2$})t \\ \\ 9\text{ m/s} & = (9.8 \text{ m/s$^2$})t \\ \\ t &\approx0.9184 \text{ s} \end{aligned}

To find how far the object dropped, we can use the second equation:

\displaystyle\begin{aligned}  \Delta d & = v_0 t + \frac{1}{2} at^2 \\ \\  & = (0\text{ m/s})(0.9184 \text{ s}) + \frac{1}{2}(9.8 \text{ m/s$^2$})(0.9184 \text{ s})^2 \\ \\ & = 4.1323 \text{ m} \end{aligned}

In conclusion, the object would have dropped about 4.1323 meters.

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Help me with this geometry question please
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