In how many ways can we seat 6 people around a round table if Fred and Gwen insist on sitting opposite each other? (Two seatings
are considered equivalent if one is a rotation of the other.)
1 answer:
Make a picture of the problem.
Fred and Gwen are seated opposite each other, and we name the 4 remaining seats 1, 2, 3, 4, starting from the right of Fred.
There are 4 options for seat 1,
then 3 for the seat 2, after one is seated in the 1.st seat
2 options for the seat 3,
and 1 for the seat 4.
That is, the 4 friends can sit in 4*3*2*1=24 different ways.
Answer: 24
Fred and Gwen are seated opposite each other, and we name the 4 remaining seats 1, 2, 3, 4, starting from the right of Fred.
There are 4 options for seat 1,
then 3 for the seat 2, after one is seated in the 1.st seat
2 options for the seat 3,
and 1 for the seat 4.
That is, the 4 friends can sit in 4*3*2*1=24 different ways.
Answer: 24
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Answer:
38.72%
Step-by-step explanation:
Estimated attendance = 1,000
The actual value of attendance = 1,632
We need to find the percent error of Shaun's estimate. Using the formula as follows :
Put all the values,
So, the percent error of Shaun's estimate is 38.72%.