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3 years ago

Which of the following values are in the range of the function graphed below? Check all that apply. HELP PLEASE !!!!!

Mathematics

1 answer:

poizon [28]3 years ago

3 0

The only answer is choice D) 6

Recall that the range is the set of possible y output values of a function. In other words, its the list of y coordinates for every point on the function curve.

In this case, the horizontal line has EVERY point on it with a y coordinate of y=6. Two such points are (0,6) and (2,6). No other y value is possible. No matter what x value we plug in, the output is always y = 6

Side Note: the domain appears to be from x = -3 to x = 5

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Mr. James has cylindrical beakers that measure 4 inches in diameter and 9 inches high. What is the volume contained within the b

goblinko [34]

So 4 inches diameter result the radius is 4/2 = 2 inches

area of base = pir^2 = 3,14*2^2 = 3,14*4 = 12,56 inches squared

volume = area of base *height

V = 12,56 *9 = 113,04 so rounded 113,05 inches cubed

hope this will help you

3 0

3 years ago

Will mark as brainliest (must show work)

Sever21 [200]

Answer:

Step-by-step explanation:

With those problems if you are not given a picture is good we draw one.

Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW then

m < XVY = m < YVW

2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms

2x-x = 15-7, combine like terms

x = 8

From the picture and the given we see that

m < XVW = m < XVY + m < YVW

m < XVW = 2x+7 + x+15 , combine like terms

m < XVW = 3x + 22, substitute x for 8

m < XVW = 3*8 + 22

m < XVW = 46

Check our work:

m < XVY = 2x+7 = 2*8 +7 = 16 +7 = 23

m < YVW = x+15 = 8 +15 = 23

m < XVW = m < XVY + m < YVW = 23+23 =46

3 0

2 years ago

for a short time after a wave is created by wind the height of the wave can be modeled using y= a sin 2pit/T where a is the ampl

dangina [55]

Answer:

y = 4 sin(t/2 + 4π/3) − 2

Step-by-step explanation:

General form:

y = a sin(2π/T t)

Given a = 4 and T = 4π:

y = 4 sin(2π/(4π) t)

y = 4 sin(t/2)

Add horizontal shift of -4π/3 and vertical shift of -2:

y = 4 sin(t/2 − (-4π/3)) − 2

y = 4 sin(t/2 + 4π/3) − 2

6 0

3 years ago

Sarah built a table uding 6 pieces of wood that were each 3 3/4 wide. How wide was the table?

prisoha [69]

The table was <em><u>22.5 inches wide</u></em>.

hope this helps!

3 0

3 years ago

Read 2 more answers

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago