-(4)-2 = -4-2= -6
Hope that helps you
The events A and B are independent events, and the values of P(A) and P(B) are 7/12 and 1/2, respectively
<h3>The value of P(A)</h3>
The event A is given as:
A : Sum greater than 6
In the sample space of a roll of two dice, there are 21 outcomes that are greater than 6, out of a total of 36 outcomes
This means that:
P(A) = 21/36
Simplify
P(A) = 7/12
<h3>The value of P(B)</h3>
The event B is given as:
B : Sum is divisible by 2
In the sample space of a roll of two dice, there are 18 outcomes that are divisible by 2, out of a total of 36 outcomes
This means that:
P(B) = 18/36
Simplify
P(B) = 1/2
Hence, the probability values of P(A) and P(B) are 7/12 and 1/2, respectively
Read more about probability at:
brainly.com/question/251701
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Answer:
Step-by-step explanation:
1km = 1000m
5a. 5.768km = 5768m = 57.7m
5b. 9.039km = 9039m = 90.4m
5c. 8.48km = 8480m = 84.8m
5d. 17.685km = 17685m = 17.7m
5e. 17.658km = 17658m = 17.7m
To round to the nearest 100m just divide by 100 and then round it off. like 57.68=57.7m because 8 is more than 5 so 6 becomes 7 to one decimal.
Rule is applied for all the other questions too.
3:1 should be the answer.
Answer:
The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
Step-by-step explanation:
Consider the provided information.
A chemical flows into a storage tank at a rate of (180+3t) liters per minute,
Let 
is the amount of chemical in the take at <em>t </em>time.
Now find the rate of change of chemical flow during the first 20 minutes.
![\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B20%7D_%7B0%7D%20%7Bc%27%28t%29%7D%20%5C%2C%20dt%20%3D%5Cleft%5B180t%2B%5Cdfrac%7B3%7D%7B2%7Dt%5E2%5Cright%5D%5E%7B20%7D_0)
So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.
