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konstantin123 [22]
3 years ago
6

When you graph a system of two linear equations, which outcome is NOT possible?

Mathematics
2 answers:
Degger [83]3 years ago
8 0

Answer:

The lines intersect in two different points so the system has two solutions.

Step-by-step explanation:

Consider the provided information.

If you draw a graph 3 possible outcomes are:

One solution: If two linear equations intersect each other at only one point.

Infinite solution: If two lines are coincident lines

No solution: If two lines never intersect each other.

For better understanding refer the figure.

So which outcomes are not possible can be:

The two lines can never intersect each other at two points.

Hence, The lines intersect in two different points so the system has two solutions is not possible outcome.

Galina-37 [17]3 years ago
4 0

Answer:

An outcome that is not possible is that the lines intersect in two different points so the system has two solutions.

Step-by-step explanation:

The two lines can never intersect each other at two points. Two lines intersects only once if they intersect otherwise they are parallel or coincide.

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HURRY PLEASE HELP
Maslowich

Answer:

2(x+3) (x+1)

Step-by-step explanation:

2x² + 8x + 6

Splitting the middle term (8x)..

2x² + 6x + 2x + 6 =0

x (2x + 6) + 1 (2x + 6)

(2x + 6) (x + 1)

2(x + 3) (x + 1)

Hence, option C. is the correct answer.

8 0
2 years ago
Please help!! i have no clue what to do and this packet is due tonight.
Stels [109]

Answer:

[D] ∞

General Formulas and Concepts:

<u>Calculus</u>

Limits

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle  \lim_{n \to \infty} s(n)<em />

<em />\displaystyle s(n) = (\frac{5}{4n^4})(3n^5 + 3n^4 + 2n^3 + n^2)<em />

<em />

<u>Step 2: Evaluate</u>

  1. Substitute in function [Limit]:                                                                           \displaystyle  \lim_{n \to \infty} (\frac{5}{4n^4})(3n^5 + 3n^4 + 2n^3 + n^2)
  2. Multiply:                                                                                                             \displaystyle  \lim_{n \to \infty} \frac{5(3n^5 + 3n^4 + 2n^3 + n^2)}{4n^4}
  3. Power Method:                                                                                                 \displaystyle  \lim_{n \to \infty} \frac{5(3n^5 + 3n^4 + 2n^3 + n^2)}{4n^4} = \infty

Since the degree of the polynomial is greater in the numerator than in the denominator, the top will always increase faster than the bottom, thus getting infinitely larger.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

7 0
3 years ago
Using the figure below, identify the measurements of Angle 3 and Angle 8.<br><br> Pls help
katrin2010 [14]

Answer:

Angle 3 is 75 degrees

Angles 8 is 105 degrees

Step-by-step explanation:

Angle 3: One line t, angle 3 and the one measure 105 are supplementary and equal to 180 degrees. Subtract 105 from 180.

Angles 8: The angle that measures 105 and angle 8 are alternate exterior angles. This means both angles are equal.

Hope this helps!

6 0
3 years ago
As a freshman, suppose you had to take two of four lab science courses, one of two literature courses, two of three math courses
Sergeeva-Olga [200]

Answer:

We have 252 different schedules.

Step-by-step explanation:

We know that as  a freshman, suppose you had to take two of four lab science courses, one of two literature courses, two of three math courses, and one of seven physical education courses.

So from 4 lab science courses we choose 2:

C_2^4=\frac{4!}{2!(4-2)!}=6

So from 2 literature courses we choose 1:

C_1^2=\frac{2!}{1!(2-1)!}=2

So from 3 math courses we choose 2:

C_2^3=\frac{3!}{2!(3-2)!}=3\\

So from 7 physical education courses we choose 1:

C_1^7=\frac{7!}{1!(7-1)!}=7

We get: 6 · 2 · 3 · 7 = 252

We have 252 different schedules.

5 0
3 years ago
Question 1(Multiple Choice Worth 2 points)
dusya [7]

Answer:

6x +47

Step-by-step explanation:

f(x) = 6x + 11

g(x) = x + 6

now f[g(x)]=<em>by</em><em> </em><em>substituting</em><em> </em><em>values</em><em> </em><em>of</em><em> </em><em>g</em><em> </em><em>(</em><em>x</em><em>)</em>

<em>to</em><em> </em><em>f</em><em> </em><em>(</em><em>x</em><em>)</em>

<em>f[g(x)]</em><em>=</em><em>6</em><em> </em><em>(</em><em>x</em><em>+</em><em>6</em><em>)</em><em>+</em><em>11</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>6x</em><em>+</em><em>36</em><em>+</em><em>11</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>6x</em><em> </em><em>+</em><em>47</em>

7 0
3 years ago
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