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3 years ago

When you graph a system of two linear equations, which outcome is NOT possible?

Mathematics

2 answers:

Degger [83]3 years ago

8 0

Answer:

The lines intersect in two different points so the system has two solutions.

Step-by-step explanation:

Consider the provided information.

If you draw a graph 3 possible outcomes are:

One solution: If two linear equations intersect each other at only one point.

Infinite solution: If two lines are coincident lines

No solution: If two lines never intersect each other.

For better understanding refer the figure.

So which outcomes are not possible can be:

The two lines can never intersect each other at two points.

Hence, The lines intersect in two different points so the system has two solutions is not possible outcome.

Galina-37 [17]3 years ago

4 0

Answer:

An outcome that is not possible is that the lines intersect in two different points so the system has two solutions.

Step-by-step explanation:

The two lines can never intersect each other at two points. Two lines intersects only once if they intersect otherwise they are parallel or coincide.

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Answer:

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Step-by-step explanation:

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3 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

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3 years ago