The height of the kite above the ground is 58.68 ft
Let x be the height of the kite above Chee's hand.
The height of the kite above Chee's hand, the string and the horizontal distance between Chee and the kite form a right angled triangle with hypotenuse side, the length of the string and opposite side the height of the kite above Chee's hand.
Since we have the angle of elevation from her hand to the kite is 29°, and the length of the string is 100 ft.
From trigonometric ratios, we have
tan29° = x/100
So, x = 100tan29°
x = 100 × 0.5543
x = 55.43 ft.
Since Chee's hand is y = 3.25 ft above the ground, the height of the kite above the ground, L = x + y
= 55.43 ft + 3.25 ft
= 58.68 ft to the nearest hundredth of a foot
So, the height of the kite above the ground is 58.68 ft
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The parabola goes down(makes a sad face) because it is negative. The answer is 0,0
6 lang yawa kaaaaaaaaaaaaaaa
Answer:
She made 792 dollars that week. I'm assuming it is just asking for the yearly commission she made. That would be 41,184 dollars a year.
Step-by-step explanation:
7200 x 0.11 = 792 Weekly
52 Weeks in a year
792 x 52 = 41184 Yearly (if that's what it's asking for)
Let's solve for x.
5x+15y=12
Step 1: Add -15y to both sides.
5x+15y+−15y=12+−15y
5x=−15y+12
Step 2: Divide both sides by 5.
5x
5
=
−15y+12
5
x=−3y+
12
5
Answer:
x=−3y+12/5
Let's solve for y.
5x+15y=12
Step 1: Add -5x to both sides.
5x+15y+−5x=12+−5x
15y=−5x+12
Step 2: Divide both sides by 15.
15y
15
=
−5x+12
15
y=
−1
3
x+
4
5
Answer:
y=-1/3x+4/5
Hope this helps!
-Josh
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