I believe it is c if i am not wrong
Answer:
![\dfrac{\sqrt[3]{95^2}}{17\cdot95^4}=\dfrac{\sqrt[3]{9\,025}}{1\,384\,660\,625}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B3%5D%7B95%5E2%7D%7D%7B17%5Ccdot95%5E4%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B9%5C%2C025%7D%7D%7B1%5C%2C384%5C%2C660%5C%2C625%7D)
Step-by-step explanation:
The applicable rules of exponents are ...
(ab)^c = (a^c)(b^c)
(a^b)/(a^c) = a^(b-c)
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![\dfrac{190^3}{68^2}\times\dfrac{34}{95^{\frac{19}{3}}}=\dfrac{(2\cdot 95)^3}{(2\cdot 34)^2}\cdot\dfrac{34}{95^6\cdot 95^{\frac{1}{3}}}=2^{3-2}95^{3-6-\frac{1}{3}}34^{1-2}\\\\=2\cdot 95^{-3\frac{1}{3}}\cdot 34^{-1}=2\cdot 95^{-4+\frac{2}{3}}\cdot 34^{-1}\\\\=\dfrac{2\sqrt[3]{95^2}}{95^4\cdot 34}=\dfrac{\sqrt[3]{95^2}}{17\cdot95^4}\\\\=\dfrac{\sqrt[3]{9\,025}}{1\,384\,660\,625}](https://tex.z-dn.net/?f=%5Cdfrac%7B190%5E3%7D%7B68%5E2%7D%5Ctimes%5Cdfrac%7B34%7D%7B95%5E%7B%5Cfrac%7B19%7D%7B3%7D%7D%7D%3D%5Cdfrac%7B%282%5Ccdot%2095%29%5E3%7D%7B%282%5Ccdot%2034%29%5E2%7D%5Ccdot%5Cdfrac%7B34%7D%7B95%5E6%5Ccdot%2095%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%7D%3D2%5E%7B3-2%7D95%5E%7B3-6-%5Cfrac%7B1%7D%7B3%7D%7D34%5E%7B1-2%7D%5C%5C%5C%5C%3D2%5Ccdot%2095%5E%7B-3%5Cfrac%7B1%7D%7B3%7D%7D%5Ccdot%2034%5E%7B-1%7D%3D2%5Ccdot%2095%5E%7B-4%2B%5Cfrac%7B2%7D%7B3%7D%7D%5Ccdot%2034%5E%7B-1%7D%5C%5C%5C%5C%3D%5Cdfrac%7B2%5Csqrt%5B3%5D%7B95%5E2%7D%7D%7B95%5E4%5Ccdot%2034%7D%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B95%5E2%7D%7D%7B17%5Ccdot95%5E4%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%5Csqrt%5B3%5D%7B9%5C%2C025%7D%7D%7B1%5C%2C384%5C%2C660%5C%2C625%7D)
Step-by-step explanation:
2 is an even number so if everytime u land on an even number u win $8 so we do this (8-2=6)
Answer:
Volume of prism = 240 ft²
Step-by-step explanation:
Given:
Base of prism (B) = 10 ft
Length of prism (L) = 8 ft
Height of prism (H) = 6 ft
Find:
Volume of prism
Computation:
Volume of prism = [BHL] / 2
Volume of prism = [(10)(8)(6)] / 2
Volume of prism = [480] / 2
Volume of prism = 240 ft²
Answer:
IT IS BOTH
Step-by-step explanation:
Given the coordinate of the triangle, P1P2P3, we are to classify the triangle. To do that we need to know the length of each side of the triangle
P1P2, P2P3 and P1P2 using the formula for calculating distance between two coordinates
D = √(x2-x1)²+(y2-y1)²
For P1P2;
P1=(−1,4) P2=(6,2)
P1P2 = √(6-(-1))²+(2-4)²
P1P2 = √7²+2²
P1P2 = √53
For P1P3;
P1=(−1,4) P3=(4,-5)
P1P3 = √(4-(-1))²+(-5-4)²
P1P3 = √5²+9²
P1P3 = √25+81
P1P3 = √106
For P2P3;
P2=(6,2) P3 = (4,-5)
P2P3= √(4-6)²+(-5-2)²
P2P3 = √2²+7²
P2P3 = √53
Since two sides of the triangles are the same, this means that it is an isosceles triangle.
Let's check whether it is right angled by applying Pythagoras theorem
(√53)²+(√53)² = x²
x is the longest side (hypotenuse)
53+53 = x²
106 = x²
x = √106
Since the square of the hypotenuse is equal to the sum of the sum of the square of other two sides, then it is also a RIGHT ANGLED TRIANGLE
